持续接受客户端连接

Question

我需要一个程序来接受来自客户端的请求，并每5秒处理一次。这是我的代码：

def run(self):
        global numConn
        numConn += 1
        print("Got connection number ",numConn)
        #print(self.ip,self.port,self.conn)
        while True :
            data = self.conn.recv(1024)
            hostname = abc   
            self.conn.send(hostname.encode())

# To process request in every 5 secs:

def printit():
    global pFlag
    threading.Timer(5.0, printit).start()
    #print("Hello the length is",len(store_thread))
    if pFlag == 0:
        pFlag = 1
        for h in store_thread:
            store_thread.remove(h)
            h.start()
        pFlag = 0

printit()

while 1:
    #print("Multithreaded Python server : Waiting for connections from TCP clients...")
    print('This is new connection')
    (conn, (ip,port)) = sock.accept()
    conn_ip_port[currentConn] = (conn,ip,port)
    currentConn += 1
    temp = 0
    newthread = ClientThread(conn_ip_port[temp][1],conn_ip_port[temp][2],conn_ip_port[temp][0])
    store_thread.append(newthread)
    temp += 1
    threads.append(newthread)
    currentConn = 0

但是在这里，一旦执行printit（）函数，它就开始接受连接。我希望它应该继续接受连接并存储在列表中，而不必等待printit（）函数完成。