Question

我想使用FSW监视文件何时由我的应用程序的同一实例打开和修改。我希望仅当我保存在同一应用程序（我们的应用程序）中两次打开过的文件时，才触发监视程序。我的问题是，即使我只打开了一个应用程序实例，也会触发该监视程序。在另一个应用程序实例中保存（修改）一个文件或从当前应用程序实例中保存相同的文件，我该如何区分？

我尝试使用集合，尝试在程序的不同部分制作this.watcher.EnableRaisingEvents = true或this.watcher.EnableRaisingEvents = false，但似乎没有什么能解决我的问题。

这是我的代码段：

private void Load(string fileName)
{
    // Only watch seq files.
    this.watcher.Path = Path.GetDirectoryName(fileName);

    // Watch for changes in LastWrite times.
    this.watcher.NotifyFilter = NotifyFilters.LastWrite;

    this.watcher.Filter = "*.zzz";

    // Add event handlers.
    this.watcher.Changed += this.OnChanged;

    // Begin watching.
    this.watcher.EnableRaisingEvents = true;

    // opened file
}

// Define the event handlers.

private void OnChanged(object source, FileSystemEventArgs e)
{
    App.Current.Dispatcher.Invoke(() =>
        {
            MessageBoxResult result = CustomMessageBox.ShowYesNoCancel(
                "The file has been modified by another instance.",
                "More app instances are opened!",
                "Overwrite",
                "Reload",
                "Save as",
                MessageBoxImage.Exclamation);

            if (result == MessageBoxResult.Yes)
            {
                // Overwrite
                this.SaveSequence();
            }

            if (result == MessageBoxResult.Cancel)
            {
                // Save as
            }

            if (result == MessageBoxResult.No)
            {
                // Reload file and lose changes
            }
        });

        // End watching.
        this.watcher.EnableRaisingEvents = false;
    }

internal bool Save()
{
    /// some code

    this.File.Write(this.FilePath); //here is the moment when my watcher is triggered

    /// rest of the code
}

在两个实例.NET中打开相同的文件

0 个答案: