Question

我想知道如何在未经授权的情况下更改express-jwt的响应，我尝试过使用处理程序，但不起作用

我需要帮助

// Authorization
const auth = require('express-jwt');

router.get('/', auth({secret: config.secretKey}),async(req,res,next)=>{
  console.log('hola')
})

当令牌无效时返回此

<!DOCTYPE html>
<html lang="en">
    <head>
        <meta charset="utf-8">
        <title>Error</title>
    </head>
    <body>
        <pre>UnauthorizedError: invalid token
            <br> &nbsp; &nbsp;at /Users/luisandrade/code/slothy_/back/node_modules/express-jwt/lib/index.js:102:22
            <br> &nbsp; &nbsp;at Object.module.exports [as verify] (/Users/luisandrade/code/slothy_/back/node_modules/jsonwebtoken/verify.js:75:12)
            <br> &nbsp; &nbsp;at verifyToken (/Users/luisandrade/code/slothy_/back/node_modules/express-jwt/lib/index.js:100:13)
            <br> &nbsp; &nbsp;at fn (/Users/luisandrade/code/slothy_/back/node_modules/express-jwt/node_modules/async/lib/async.js:746:34)
            <br> &nbsp; &nbsp;at /Users/luisandrade/code/slothy_/back/node_modules/express-jwt/node_modules/async/lib/async.js:1213:16
            <br> &nbsp; &nbsp;at /Users/luisandrade/code/slothy_/back/node_modules/express-jwt/node_modules/async/lib/async.js:166:37
            <br> &nbsp; &nbsp;at /Users/luisandrade/code/slothy_/back/node_modules/express-jwt/node_modules/async/lib/async.js:706:43
            <br> &nbsp; &nbsp;at /Users/luisandrade/code/slothy_/back/node_modules/express-jwt/node_modules/async/lib/async.js:167:37
            <br> &nbsp; &nbsp;at Immediate._onImmediate (/Users/luisandrade/code/slothy_/back/node_modules/express-jwt/node_modules/async/lib/async.js:1206:34)
            <br> &nbsp; &nbsp;at runCallback (timers.js:810:20)
            <br> &nbsp; &nbsp;at tryOnImmediate (timers.js:768:5)
            <br> &nbsp; &nbsp;at processImmediate [as _immediateCallback] (timers.js:745:5)
        </pre>
    </body>
</html>

但是我想要这个

{
  error: 'some message'
}

Answer 1

将其放在创建服务器的位置上方。

app.use(function (err, req, res, next) {
    if (err.name === 'UnauthorizedError') {
        res.status(401).send('invalid token...');
    }
});

您还可以使用next(e)处理其他错误，其中e是try catch中的错误。

如何将express-jwt的默认响应更改为自定义响应？

1 个答案: