如何使用PHP修复“ Ajax表单提交”

时间:2019-04-18 19:35:06

标签: javascript php ajax

下面显示的代码使用了Ajax,但是有一个不确定的加载条,就好像从未从控制器调用该函数一样。我将如何使HTML成功启动此功能?

//HTML
<button type="button" data-url="/ajax/controller.php" name="dosubmit" class="wojo button positive">Approve</button>
<input name="ProcessApproval" type="hidden" value="1">
//Function
public function ProcessPOApproval()
      {    
        $PID = $_GET['pid'];

        $ApprovalTransactionalData = array(
            'PONum' => "$PID",
            'Step' => "4"
        );
        self::$db->insert("accounting_transact", $ApprovalTransactionalData);
}
//Controller
<?php
 /* == Proccess Project File == */
 if (isset($_POST['ProcessApproval'])):
    if (intval($_POST['ProcessApproval']) == 0 || empty($_POST['ProcessApproval'])):
        die();
    endif;
    ProcessPOApproval();
endif;
?>
     //Ajax
       /* == Master Form == */
       $('body').on('click', 'button[name=dosubmit]', function() {
           posturl = $(this).data('url')

           function showResponse(json) {
               if (json.status == "success") {
                   $(".wojo.form").removeClass("loading").slideUp();
                   $("#msgholder").html(json.message);
               } else {
                   $(".wojo.form").removeClass("loading");
                   $("#msgholder").html(json.message);
               }
           }

           function showLoader() {
               $(".wojo.form").addClass("loading");
           }
           var options = {
               target: "#msgholder",
               beforeSubmit: showLoader,
               success: showResponse,
               type: "post",
               url: SITEURL + posturl,
               dataType: 'json'
           };

           $('#wojo_form').ajaxForm(options).submit();
       });

下面是具有wojo_form id的HTML。

    <form id="wojo_form" name="wojo_form" method="post">
    <div class="three fields">
      <div class="field">
        <label>Submitting Accountant</label>
        <label class="input"><i class="icon-prepend icon calendar"></i>
          <input type="text" value="" disabled="disabled" name="created">
        </label>
      </div>
      <div class="field">
        <label>Next Approval</label>
        <label class="input"><i class="icon-append icon calendar"></i>
          <input type="text" value="<?php echo $row->lastlogin;?>" disabled="disabled" name="lastlogin">
        </label>
      </div>
      <div class="field">
        <label>Approval Group</label>
        <label class="input"><i class="icon-prepend icon laptop"></i>
          <input type="text" value="<?php echo $row->lastip;?>" disabled="disabled" name="lastip">
        </label>
      </div>
    </div>
    <div class="wojo double fitted divider"></div>
    <button type="button" data-url="/ajax/controller.php" action="" name="dosubmit" class="wojo button">Decline Approval</button>
    <input name="ProcessDecline" type="hidden" value="1">
    <button type="button" data-url="ajax/controller.php" name="dosubmit" class="wojo button positive">Approve</button>
    <input name="ProcessApproval" type="hidden" value="1">
    <button type="button" data-url="/ajax/controller.php" name="dosubmit" class="wojo button info">Add Notes</button>
    <input name="ProcessNotes" type="hidden" value="1">
  </form>

如果您需要其他任何东西,请告诉我。

0 个答案:

没有答案