创建一个共享链接api_create

时间:2019-04-18 16:54:01

标签: plotly r-plotly

我想分享我用图绘制的图

“我尝试了Sys.setenv(“ plotly_domain” =“ https://plot.ly/~tariq566.com”),然后创建了图表链接chart_link = api_create(pN,filename =“ rf”)“ < / p>

df4 <- data.frame(Group=rep(c("No pre op CKD", "Stage 1-4", "ESRD"), each=9),
                  Year=rep(c("2006","2007","2008","2009","2010","2011","2012","2013","2014"),3),
                  len=c(7.79 ,4.41,3.87,4.45,3.87,4.75,3.93,3.17,3.86,
                        4.35 ,2.97,4.85,4.28,4.48,4.69,3.88,2.66,3.25,
                        13.33,14.29,9.38,12.22,7.29,7.25,10.08,11.72,16.67))

df4$Group<-factor(df4$Group, levels=c("No pre op CKD", "Stage 1-4", "ESRD"))

pN <- df4 %>%
  plot_ly(
    x = ~Group, 
    y = ~len, 
    size = ~len, 
    color = ~Group, 
    frame = ~Year, 
    text = ~Group, 
    hoverinfo = "text",
    type = 'bar',
    yaxis = list(title = 'Mortality (%)')
  ) %>%
  layout(
    xaxis = list(
      title = "Groups"),
yaxis = list(title = 'Mortality (%)',barmode = 'Group')
)

Sys.setenv("plotly_domain"="https://plot.ly/"username.com")

chart_link= api_create(pN,filename="rf")


##Error: lexical error: invalid char in json text.
                                       <!DOCTYPE html> <html class="ba
                     (right here) ------^

0 个答案:

没有答案