Question

我想传递两个名称数组，这样它将返回一个包含出现在两个或两个数组中的名称的数组。返回的数组应该没有重复。

例如，调用MergeNames.uniqueNames(new String[]{'Ava', 'Emma', 'Olivia'}, new String[]{'Olivia', 'Sophia', 'Emma'})应该以任意顺序返回包含Ava，Emma，Olivia和Sophia的数组。

需要基本实现uniqueNames方法。抱歉，我是Java编程的新手，并尝试通过编码挑战来成为一名开发人员。

public class MergeNames {

    public static String[] uniqueNames(String[] names1, String[] names2) {
        throw new UnsupportedOperationException("Waiting to be implemented.");      
    }

    public static void main(String[] args) {
        String[] names1 = new String[] {"Ava", "Emma", "Olivia"};
        String[] names2 = new String[] {"Olivia", "Sophia", "Emma"};
        System.out.println(String.join(", ", MergeNames.uniqueNames(names1, names2))); // should print Ava, Emma, Olivia, Sophia
    }
}

******我的解决方案任何反馈欢迎******

import java.util.*;

public class MergeNames {

public static void main(String[] args) {

    String[] names1 = new String[] {"Ava", "Emma", "Olivia"};
    String[] names2 = new String[] {"Olivia", "Sophia", "Emma"};

    Set<String> mySet1 = new HashSet<String>(Arrays.asList(names1));
    Set<String> mySet2 = new HashSet<String>(Arrays.asList(names2));

    Set<String> union = new HashSet<String>(mySet1);
    union.addAll(mySet2);
    System.out.println("Union of the two Sets with no duplicate names : " + union);

}
}

我不确定为什么需要uniqueNames函数吗？

Answer 1

在注释中，您提到必须使用另一种方法来执行此操作，并将 joint数组作为参数返回给main() 。好的，我认为这意味着您必须将联合数组return回到main()“不作为参数”

您可以这样：

import java.util.*;

public class MergeNames 
{
    public static void main(String[] args) 
    {
        String[] names1 = new String[] {"Ava", "Emma", "Olivia"};
        String[] names2 = new String[] {"Olivia", "Sophia", "Emma"};
        String[] Names = mergeNames(names1, names2);
        for(String n: Names)
            System.out.print(" "+ n);
    }

    public static String[] mergeNames(String[] n1, String[] n2)
    {
        Set<String> mySet1 = new HashSet<String>(Arrays.asList(n1));
        Set<String> mySet2 = new HashSet<String>(Arrays.asList(n2));
        Set<String> union = new HashSet<String>(mySet1);
        union.addAll(mySet2);
        return  union.toArray(new String[union.size()]);
    }
}

Answer 2

如@junvar所建议，请看java.util.Set

创建一个new java.util.TreeSet<String> myset
遍历每个数组，并为每个名称值调用myset.add()。 Set将为您删除重复项
要将集合转换回数组，请参见Converting Set<String> to String array

祝你好运！

如何返回包含两个数组中出现的值的数组？而且没有重复

2 个答案: