Question

我想使用Symfony XML序列化器转换类实例（而不是数组）。因此，例如，我想使用属性myAtt =“ foo”创建这样的XML，

<?xml version="1.0"?>
<REQ>
    <TravelAgencySender myAtt="foo">
        <CityName>town</CityName>
        <AgencyID>agency</AgencyID>
    </TravelAgencySender>   
</REQ>

所以我创建了一个像这样的类

class TravelAgencySender 
{

    /**
     * @var string
     */
    private  $CityName;
    /**
     * @var string
     */
    public  $AgencyID;
.....
}

以及以下初始化

use Symfony\Component\Serializer\Encoder\JsonEncoder;
use Symfony\Component\Serializer\NameConverter\MetadataAwareNameConverter;
use Symfony\Component\Serializer\Normalizer\ObjectNormalizer;
use Symfony\Component\Serializer\Serializer;
use Symfony\Component\Serializer\Encoder\XmlEncoder;
use Symfony\Component\Serializer\Mapping\Factory\ClassMetadataFactory;
use Symfony\Component\Serializer\Mapping\Loader\AnnotationLoader;
use Doctrine\Common\Annotations\AnnotationReader;



$classMetadataFactory = new ClassMetadataFactory(new AnnotationLoader(new AnnotationReader()));

$metadataAwareNameConverter = new MetadataAwareNameConverter($classMetadataFactory);

$serializer = new Serializer(
    [new ObjectNormalizer($classMetadataFactory, $metadataAwareNameConverter)],
    ['json' => new JsonEncoder(), 'xml' => new XmlEncoder()]
);

有人知道如何添加myAtt属性吗？

谢谢

这将产生以下XML

<?xml version="1.0"?>
<REQ>
    <TravelAgencySender>
        <CityName>town</CityName>
        <AgencyID>agency</AgencyID>
    </TravelAgencySender>   
</REQ>

Answer 1

以@开头的数组键被视为XML属性：

['foo' => ['@bar' => 'value']];

编码如下：

<?xml version="1.0"?>
<response>
     <foo bar="value"/>
</response>

Symfony序列化器XML属性

1 个答案: