如何根据用户类型获得各个阶段?

时间:2019-04-18 12:35:19

标签: java sqlite javafx scenebuilder

所以现在的问题是,我无法针对每种类型的用户向正确的阶段进行提示,我有一种方法来检查其用户名并返回其角色类型,然后将其提示到各自的阶段验证他们的用户并通过后。

我已经尝试进行一些调试,并且似乎getUserRole方法存在问题,因为我无法在登录控制器中找到该方法。

**登录控制器*

@FXML
    public void Login(ActionEvent event) {
        try {
            if (this.loginModel.isLogin(this.username.getText(), this.password.getText())) {
                Stage stage = (Stage) this.login.getScene().getWindow();
                stage.close();

                if (this.loginModel.getUserRole(this.username.getText()) == 5) {
                    adminLogin();
                } else if (this.loginModel.getUserRole(this.username.getText()) == 4) {
                    technicianLogin();
                } else if (this.loginModel.getUserRole(this.username.getText()) == 3) {
                    custServiceLogin();
                } else if (this.loginModel.getUserRole(this.username.getText()) == 3) {
                    financeLogin();
                } else if (this.loginModel.getUserRole(this.username.getText()) == 3) {
                    managementLogin();
                } else {
                    this.loginStatus.setText("The username or password entered is incorrect. Please check and try again.");
                }

            }
        } catch (Exception localException) {
            this.loginStatus.setText("The username or password entered is incorrect. Please check and try again.");
        }
    }

获取UserRole方法

public int getUserRole(String user) throws Exception
    {
     PreparedStatement pr = null;
     ResultSet rs = null;

     String sql = "SELECT * FROM Login WHERE username = ? AND role = ?";
     try
     {
         pr = this.connection.prepareStatement(sql);
         pr.setString(1, user);


         if(rs.next())//cant initialized this if statement
         {
             int role = rs.getInt("role");
             return role;
         }
         else{
             return 0;
         }
     }
     catch(SQLException ex)
     {
         return 0;
     }

     finally
     {
     pr.close();
     rs.close();
     }


    }

1 个答案:

答案 0 :(得分:0)

我找到了一个解决方案,似乎我忘记了执行查询,将其添加到try块中后,似乎可以正常工作。

rs.executeQuery();