Question

我有一个来自excel文件的数组。

   $array = [
     ['parent 1', '10000', '20000'],
     ['parent 1', '15000', '21000'],
     ['parent 2', '13000', '22000'],
     ['parent 2', '11000', '5000'],
   ];

如何使用php将上面的数组转换为下面的数组

   $array = [
     'parent 1' => [
        ['10000', '20000'],
        ['15000', '21000']
     ],
     'parent 2' => [
        ['13000', '22000'],
        ['11000', '5000']
     ]
   ];

Answer 1

您需要遍历数组以将第一个值作为键并保留其值。

版本1

$result = [];
foreach ($arr as $k => $v) {
    $result[$v[0]][] = [ // making first value as key and reset its values
        $v[1], $v[2],
    ];
}
print_r($result);

Demo。

编辑

版本2

$result = [];
foreach ($arr as $k => $v) {
    $result[array_shift($v)][] = $v;
}
print_r($result);

输出

Array
(
    [parent 1] => Array
        (
            [0] => Array
                (
                    [0] => 10000
                    [1] => 20000
                )

            [1] => Array
                (
                    [0] => 15000
                    [1] => 21000
                )

        )

    [parent 2] => Array
        (
            [0] => Array
                (
                    [0] => 13000
                    [1] => 22000
                )

            [1] => Array
                (
                    [0] => 11000
                    [1] => 5000
                )

        )

)

Answer 2

尝试这个简单而精确的解决方案。

$array = [
   ['parent 1', '10000', '20000'],
   ['parent 1', '15000', '21000'],
   ['parent 2', '13000', '22000'],
   ['parent 2', '11000', '5000'],
 ];

$output = [];
foreach ($array as $key => $value) {
    $output[$value[0]][] = array($value[1],$value[2]);
}
print_r($output);

parent 1和parent 2位于0索引上，其他实体位于1和2索引上。我在每次迭代时都将1和2的索引值分配给新数组中的0索引

输出

    Array
(
    [parent 1] => Array
        (
            [0] => Array
                (
                    [0] => 10000
                    [1] => 20000
                )

            [1] => Array
                (
                    [0] => 15000
                    [1] => 21000
                )

        )

    [parent 2] => Array
        (
            [0] => Array
                (
                    [0] => 13000
                    [1] => 22000
                )

            [1] => Array
                (
                    [0] => 11000
                    [1] => 5000
                )

        )

)

这里是demo

Answer 3

这是一个解决方案：

演示：https://3v4l.org/XoivL

import { StyleSheet, View, Alert, Platform, Button } from 'react-native';

export default class MyProject extends Component {

  constructor(props) {

       super(props)

      Obj = new Second();

     }

     CallFunction_1=()=>{

      Obj.SecondClassFunction() ;

     }

     CallFunction_2=()=>{

            Obj.SecondClassFunctionWithArgument("Hello Text");

    }

  render() {

    return (

      <View style={styles.MainContainer}>

        <View style={{margin: 10}}>

          <Button title="Call Another Class Function Without Argument" onPress={this.CallFunction_1} />

        </View>

        <View style={{margin: 10}}>

          <Button title="Call Another Class Function With Argument" onPress={this.CallFunction_2} />

        </View>

      </View>

    );
  }
}

class Second extends Component {

  SecondClassFunction=()=>{

    Alert.alert("Second Class Function Without Argument Called");

  }

  SecondClassFunctionWithArgument=(Value)=>{

    Alert.alert(Value);

  }

}

const styles = StyleSheet.create(
{
  MainContainer: {
    justifyContent: 'center',
    alignItems: 'center',
    flex: 1,
    backgroundColor: '#F5FCFF',
    paddingTop: (Platform.OS) === 'ios' ? 20 : 0
  }

});

输出：

   $array = [
     ['parent 1', '10000', '20000'],
     ['parent 1', '15000', '21000'],
     ['parent 2', '13000', '22000'],
     ['parent 2', '11000', '5000'],
   ];


    $new_array = array();

    foreach($array as $a) {
       $temp = array_slice($a, 1);

      if(!array_key_exists($a[0], $new_array)) {
          $new_array[$a[0]] = array();
      }

       array_push($new_array[$a[0]], $temp);

    }

    print_r($new_array)

如何在PHP上将数组从单数组转换为多维数组

3 个答案: