Question

我正在尝试使用杰克逊将对象转换为xml

XmlMapper xmlMapper = new XmlMapper();
            xmlMapper.configure(ToXmlGenerator.Feature.WRITE_XML_DECLARATION, true);
            xmlMapper.writeValue(createFileResult.getFile(), detailsProductDTOs);

但是，由于我的对象在某处包含xml无效字符，因此出现错误。有什么方法可以告诉杰克逊忽略这种字符吗？或任何其他解决方案？

Caused by: java.io.IOException: Invalid white space character (0xb) in text to output (in xml 1.1, could output as a character entity)
    at com.ctc.wstx.api.InvalidCharHandler$FailingHandler.convertInvalidChar(InvalidCharHandler.java:56)
    at com.ctc.wstx.sw.XmlWriter.handleInvalidChar(XmlWriter.java:629)
    at com.ctc.wstx.sw.BufferingXmlWriter.writeCharacters(BufferingXmlWriter.java:583)
    at com.ctc.wstx.sw.BaseStreamWriter.writeCharacters(BaseStreamWriter.java:469)
    at com.fasterxml.jackson.dataformat.xml.ser.ToXmlGenerator.writeString(ToXmlGenerator.java:588)

Answer 1

最后，我自己解决了这个问题。如错误指示xml 1.1支持此类字符。因此，只需添加以下配置即可解决该问题：

xmlMapper.configure(ToXmlGenerator.Feature.WRITE_XML_1_1, true);

Java，杰克逊，将对象转换为xml，字符无效的问题

1 个答案: