Question

表格中的特定列中，工作人员讲述了付款或收据的性质。

编写类似'PAYMENT OF SALARIES FOR THE MONTH OF NOVEMBER 2018'之类的东西。我希望能够有一些代码（ORACLE SQL）从这些叙述中挑选几个月。

Answer 1

您可以连续使用基于正则表达式的函数（_replace，_substr，_count）提取月份名称，前提是所有具有相同格式模型的数据都以“月份年份”组合结尾

with t(str) as
(
 select 'PAYMENT OF SALARIES FOR THE MONTH OF NOVEMBER 2018' from dual
), t2 as
(
select rtrim(str,regexp_replace(str,'(\D)')) as str       
  from t
), t3 as
(  
select regexp_substr(str,'[^ ]+',1,level) as str, 
       regexp_count(str,'[^ ]+') as cnt,
       level as lvl 
  from t2
 connect by level <= regexp_count(str,'[^ ]+')
)
select str 
  from t3 
 where lvl = cnt;

STR
--------
NOVEMBER

Answer 2

即使您指定的文本格式相同，它也会起作用：

 select * from (select rownum, regexp_substr("column1",'[^ ]+', 1, level) from Table1
 connect by regexp_substr("column1", '[^ ]+', 1, level) is not null) where rownum<=8
 minus
 select * from (select rownum, regexp_substr("column1",'[^ ]+', 1, level) from Table1
 connect by regexp_substr("column1", '[^ ]+', 1, level) is not null) where rownum<8;

http://sqlfiddle.com/#!4/560dc/13

Answer 3

 where
  Date >= to_date(substr(:from_date ,1,10),'YYYY/MM/DD') 
  and 
  Date <= to_date(substr(:last_date,1,10),'YYYY/MM/DD')

如何搜寻文字

3 个答案: