Question

我正在使用tkinter使用不同矩形的高度开发排序可视化程序。我能够将每个矩形的高度随机化，但是现在我不得不尝试找出如何彼此切换两个矩形的位置。在开始尝试执行排序之前，我需要弄清楚该怎么做。

这是我到目前为止所拥有的：

lambda_risk@value= 0
is_dcp( log_sum_exp( log(ps) - lambda_risk * log(rets %*% b) ) )

Answer 1

这是一个入门的小例子：单击交换按钮时，它将交换位置10的矩形和位置20的矩形。

import tkinter as tk
import random


def swap_two_pos(pos_0, pos_1):
    """This does the graphical swapping of the rectangles on the canvas
    by moving one rectangle to the location of the other, and vice versa
    """    
    x_00, _, x_01, _ = canvas.coords(pos_0)
    x_10, _, x_11, _ = canvas.coords(pos_1)
    # moves each rectangle to the x position of the other; y remains unchanged
    canvas.move(pos_0, x_10-x_00, 0)
    canvas.move(pos_1, x_01-x_11, 0)


def random_sort():
    """Not a sort yet, but you have the bare bones operations
    so the swap is executed
    """
    pos_0 = barList[10]
    pos_1 = barList[20]
    swap_two_pos(pos_0, pos_1)
    # it is necessary to swap the values in the list too
    barList[10], barList[20] = barList[20], barList[10]


window = tk.Tk()
window.title('Sorting')
window.geometry('600x400')

# button to command the swap
tk.Button(window, text='swap', command=random_sort).pack()

xstart = 5
xend = 15
canvas = tk.Canvas(window, width='600', height='400')
canvas.pack()
barList = []
lengthList = []

for x in range(1,60):
    randomY = random.randint(1,390)
    bar = canvas.create_rectangle(xstart, randomY, xend, 395, fill='red')
    barList.append(bar)
    xstart += 10
    xend +=10

for bar in barList:
    x = canvas.coords(bar)
    length = x[3]-x[1]
    lengthList.append(length)

# hardcoded colors so the swap is more visual
canvas.itemconfig(barList[10], fill='blue')
canvas.itemconfig(barList[20], fill='yellow')

window.mainloop()

如何在Tkinter画布上交换两个对象的位置

1 个答案: