Question

到目前为止我尝试过的查询

select sum(g1.datacount) from
(select DAte(DATE) as 'newdate', COUNT(RIDE_ID) as 'datacount' from 
ride_Data
where date(date) between (now() - interval 90 day) and now()
group by date(date)
order by date(date) desc) as g1
where g1.newdate between (now() - interval 7 day) and now()

上述查询的简短版本，仅供说明。

select sum(g1.datacount) from g1
where g1.newdate between (now() - interval 7 day) and now()

我想实现的目标 我想对列datacount上的最后7天求和，因为您可以看到我现在已经正确完成了这部分操作，但是在实际情况下，我希望对7天对中的最后90天求和我不知道如何将其分组？

有什么我可以将我的最后7条记录结果分组的

Answer 1

如果要与现在进行比较，则可以使用DATEDIFF和DIV 7进行分组。

SELECT ((DATEDIFF(t.newdate, NOW())) DIV 7) AS WeekDiff,
-- MIN(t.newdate) AS MinDate,
-- MAX(t.newdate) AS MaxDate,
 COUNT(t.RIDE_ID) as TotalRides
FROM ride_Data t
WHERE t.newdate BETWEEN (NOW() - interval 90 day) AND NOW()
GROUP BY WeekDiff
ORDER BY WeekDiff DESC;

或者只是在week上分组。

SELECT YEAR(t.newdate)*100+WEEK(t.newdate, 3) AS WeekNr,
COUNT(t.RIDE_ID) as TotalRides
FROM ride_Data t
WHERE t.newdate BETWEEN (NOW() - interval 90 day) AND NOW()
GROUP BY WeekNr
ORDER BY WeekNr DESC;

我陷入逻辑也许我做错了SQL

1 个答案: