为什么我要提出一个使用Moya和RxSwift的解决方案,该解决方案可以更新身份验证令牌并重试请求。
问题是我同时有多个请求,因此可以说有10个请求在身份验证令牌到期时触发,我将尝试在所有令牌上续签该令牌,并且第一个续订后其他的将失败,因为它们使用了错误的令牌进行续签。
我想做的只是建立(也许)一个请求队列,然后重试这些请求。不确定这是否是最佳方案。
这是我到目前为止所拥有的:
final class NetworkOnlineProvider {
fileprivate let database = DatabaseClient(database: DatabaseRealm()).database
fileprivate let provider: MoyaProvider<NetworkAPI>
init(endpointClosure: @escaping MoyaProvider<NetworkAPI>.EndpointClosure = MoyaProvider<NetworkAPI>.defaultEndpointMapping,
requestClosure: @escaping MoyaProvider<NetworkAPI>.RequestClosure = MoyaProvider<NetworkAPI>.defaultRequestMapping,
stubClosure: @escaping MoyaProvider<NetworkAPI>.StubClosure = MoyaProvider.neverStub,
manager: Manager = MoyaProvider<NetworkAPI>.defaultAlamofireManager(),
plugins: [PluginType] = [],
trackInflights: Bool = false) {
self.provider = MoyaProvider(endpointClosure: endpointClosure, requestClosure: requestClosure, stubClosure: stubClosure, manager: manager, plugins: plugins, trackInflights: trackInflights)
}
fileprivate func getJWTRenewRequest() -> Single<Response>? {
if let token = JWTManager.sharedInstance.token {
return provider.rx.request(.renew(token: token))
}
return nil
}
func tokenRequest() -> Single<String> {
let errorSingle = Single<String>.create { single in
single(.error(APIError.failure))
return Disposables.create()
}
let emptyJWTSingle = Single<String>.create { single in
single(.success(""))
return Disposables.create()
}
// Return if no token found
guard let appToken = JWTManager.sharedInstance.getJWT() else {
return refreshToken() ?? emptyJWTSingle
}
// If we have a valid token, just return it
if !appToken.hasTokenExpired {
return Single<String>.create { single in
single(.success(appToken.token))
return Disposables.create()
}
}
// Token has expired
let newTokenRequest = refreshToken()
return newTokenRequest ?? errorSingle
}
func refreshToken() -> Single<String>? {
return getJWTRenewRequest()?
.debug("Renewing JWT")
.filterSuccessfulStatusCodes()
.map { (response: Response) -> (token: String, expiration: Double) in
guard let json = try? JSON(data: response.data) else { throw RxError.unknown }
let success = json["success"]
guard
let jwt = success["jwt"].string,
let jwt_expiration = success["jwt_expiration"].double,
let valid_login = success["valid_login"].bool, valid_login
else { throw RxError.unknown }
return (token: jwt, expiration: jwt_expiration)
}
.do(onSuccess: { (token: String, expiration: Double) in
JWTManager.sharedInstance.save(token: JWT(token: token, expiration: String(expiration)))
})
.map { (token: String, expiration: Double) in
return token
}
.catchError { e -> Single<String> in
print("Failed to Renew JWT")
JWTManager.sharedInstance.delete()
UIApplication.shared.appDelegate.cleanPreviousContext(jwt: true)
let loginVC = UIStoryboard(storyboard: .login).instantiateViewController(vc: LoginViewController.self)
UIApplication.shared.appDelegate.window?.setRootViewController(UINavigationController(rootViewController: loginVC))
throw e
}
}
func request(_ target: NetworkAPI) -> Single<Response> {
let actualRequest = provider.rx.request(target)
if target.isAuthenticatedCall {
return tokenRequest().flatMap { _ in
actualRequest
}
}
return actualRequest
}
}
答案 0 :(得分:1)
解决方案在这里:RxSwift and Retrying a Network Request Despite Having an Invalid Token
关键是使用flatMapFirst,因此您只对第一个401发出一个请求,而在该请求进行期间忽略其他401。
与本文相关的要点包括证明其有效的单元测试。