SQL COUNT（DISTINCT（field1））GROUP BY MAX（filed2）

Question

我有一张类似的桌子

name  num_try

John     2
John     1
Mike     3
Mike     2
Linda    2

我想知道按MAX(num_try)来计数不同的名称组。

所需的结果应为

MAX(num_try)  COUNT(DISTINCT(names))
     2            2
     3            1

您能帮我这个疑问吗？

Answer 1

select max_num_try, count(*) from 
(
   select name, max(num_try) as max_num_try
   from table1
   group by name
) a
group by max_num_try
order by max_num_try desc