Question

我希望对SQL计数查询的结果数进行计数，当前结果有50个结果，但实际上只有5个结果...结果以如下格式显示：

test1-helpme1
test1-helpme3
test1-helpme4
test2-helpme1
test2-helpme2
test3-helpme4

有没有一种方法可以只计算结果的“ testx-”部分？可能有数百个结果，所以“测试”的数字部分不能硬编码

SELECT COUNT(*) as CountbyID, OriginalId FROM Table1 GROUP BY OriginalId;

Answer 1

如果您想要模式的不同出现次数，则：

SELECT 
  COUNT(DISTINCT LEFT(OriginalId, INSTR(OriginalId, '-') - 1)) as counter
FROM Table1

或每个计数器：

SELECT 
  LEFT(OriginalId, INSTR(OriginalId, '-') - 1) pattern,
  COUNT(*) as counter
FROM Table1
GROUP BY LEFT(OriginalId, INSTR(OriginalId, '-') - 1)

Answer 2

是的，您可以使用LEFT对字符串的子集进行分组：

declare @test as table (test varchar(100))

insert into @test
Select 'test1-helpme1' UNION ALL
Select 'test1-helpme3' UNION ALL
Select 'test1-helpme4' UNION ALL
Select 'test2-helpme1' UNION ALL
Select 'test2-helpme4'

Select count(*) as countbyID, left(test,5) as originalid from @test group by left(test,5)

如何计算连字符前的结果总数？

2 个答案: