Question

const usersLanguageData = {
  transactionId: 6847655349501841000,
  count: 5,
  providerList: [
    {
      code:['US'],
      weekendOfficeHours: false
    },
    {
      code:['US','IND'],
      weekendOfficeHours: true
    },
    {
      code:['US','IND','AUS'],
      weekendOfficeHours: false
    },
    {
      code:[],
      weekendOfficeHours: false
    },
    {
      weekendOfficeHours: true
    }
  ]
};

let filterKeyName1 = ["code"];
let filterValue1 = ['IND','US'];
//let filterValue2 = ['US'];
let filteredProviderData = usersLanguageData.providerList.filter(function(e) {
  return filterKeyName1.every(function(a) {
      console.log(e[a])
      return filterValue1.includes(e[a]);
  });
});

console.log(filteredProviderData);

此处的代码段将usersLanguageData显示为对象形式。在这里我想用关键字说来过滤值，例如在这里 filterKeyName1 = ['code']和filterValue1 = ['IND'，'US']，它将把第二个和第三个对象显示到usersLanguageData对象中。同样，在注释行中也有filterValue2，它将显示usersLanguageData中的1st，2nd和3rd对象。

Answer 1

您应该在函数内再次使用every()。并且还可以在使用e[a]之前先检查every()是否存在，因为您的商品之一没有code键

const usersLanguageData = { transactionId: 6847655349501841000, count: 5, providerList: [ { code:['US'], weekendOfficeHours: false }, { code:['US','IND'], weekendOfficeHours: true }, { code:['US','IND','AUS'], weekendOfficeHours: false }, { code:[], weekendOfficeHours: false }, { weekendOfficeHours: true } ] };

let filterKeyName1 = ["code"];
let filterValue1 = ['IND','US'];
//let filterValue2 = ['US'];
let filteredProviderData = usersLanguageData.providerList.filter(function(e) {
  return filterKeyName1.every(function(a) {
      console.log(e[a])
      return e[a] && filterValue1.every(x => e[a].includes(x));
  });
});

console.log(filteredProviderData);

Answer 2

您可以使用值进行过滤，并针对对象的属性或空数组进行过滤。

const usersLanguageData = { transactionId: 6847655349501841000, count: 5, providerList: [{ code: ['US'], weekendOfficeHours: false }, { code: ['US','IND'], weekendOfficeHours: true }, { code: ['US','IND','AUS'], weekendOfficeHours: false }, { code: [], weekendOfficeHours: false }, { weekendOfficeHours: true }] };

let key = "code";
let values = ['IND','US'];
let result = usersLanguageData.providerList
    .filter(o => values.every(v => (o[key] || []).includes(v)));

console.log(result);

如何使用键多个值在数组内过滤数组？

2 个答案: