Question

我正在尝试在服务器上传图片，下面是我在互联网上找到的脚本，并在本地工作，当我部署代码和数据库时，给我“未能打开流：权限被拒绝”错误。

<?php
//define a maxim size for the uploaded images in Kb
 define ("MAX_SIZE","5000"); 

//This function reads the extension of the file. It is used to determine if the file  is an image by checking the extension.
 function getExtension($str) {
         $i = strrpos($str,".");
         if (!$i) { return ""; }
         $l = strlen($str) - $i;
         $ext = substr($str,$i+1,$l);
         return $ext;
 }

//This variable is used as a flag. The value is initialized with 0 (meaning no error  found)  
//and it will be changed to 1 if an errro occures.  
//If the error occures the file will not be uploaded.
 $errors=0;

    //reads the name of the file the user submitted for uploading
    $image=$_FILES['image']['name'];

    //if it is not empty
    if ($image) 
    {
    //get the original name of the file from the clients machine
        $filename = stripslashes($_FILES['image']['name']);
    //get the extension of the file in a lower case format
        $extension = getExtension($filename);
        $extension = strtolower($extension);
    //if it is not a known extension, we will suppose it is an error and will not  upload the file,  
    //otherwise we will do more tests
 if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png")) 
        {
        //print error message
            echo '<h1>Nepoznata vrsta fajla!</h1>';
            $errors=1;
        }
        else
        {
//get the size of the image in bytes
 //$_FILES['image']['tmp_name'] is the temporary filename of the file
 //in which the uploaded file was stored on the server
 $size=filesize($_FILES['image']['tmp_name']);

//compare the size with the maxim size we defined and print error if bigger
if ($size > MAX_SIZE*1024)
{
    echo '<h1>To large file!</h1>';
    $errors=1;
}

//we will give an unique name, for example the time in unix time format
$image_name=time().'.'.$extension;
//the new name will be containing the full path where will be stored (images folder)
$newname="Content/Images/".$image_name;
//we verify if the image has been uploaded, and print error instead
//$copied = copy($_FILES['image']['tmp_name'], $newname);

$copied = copy('$_FILES['image']['tmp_name'], $newname);

//echo $_FILES['image']['tmp_name'].'<br/>';
//echo $_FILES['image']['name'];

if (!$copied) 
{
    echo '<h1>Error occurred!</h1>';
    $errors=1;
}}}


//If no errors registred, print the success message
 /*if(isset($_POST['Submit']) && !$errors) 
    {
    echo "<h1>You have successfully uploaded image.</h1>";
}*/

 ?>

我在stackoverflow中看到了一些回复，例如answers1和answer2，但我不知道该怎么做？还有其他建议吗？

感谢。

Answer 1

确保将保存文件（tmp）的文件夹权限设置为777。在终端上输入chmod -R 777 path

Answer 2

您尝试复制文件的文件夹必须与您的PHP用户具有相同的权限。（如果您的服务器是apache，则为apache用户）

./
drwxrwxr-x root root应用程序
drwxrwxr-x apache apache FilesystemDir

Answer 3

如果您也无法在目标文件夹中创建文件，并且您已经对其进行了许可755请检查以下内容：

如果您的文件是：/path/to/test-in.txt

你应该拥有X权限：

/路径
/路径/到
和/path/to/test-in.txt

在此查看更多详情 fopen() fails to open stream: permission denied, yet permissions should be valid

Answer 4

您的复制命令似乎有语法错误：

$copied = copy('$_FILES['image']['tmp_name'], $newname);
               ^--- extra quote?

如果您正在尝试执行类似

的操作

$copied = copy("$_FILES['image']['tmp_name']", $newname);

它无论如何都行不通。 PHP的解析器不是很好，并且会将其视为

$_FILES['image'] -> array
['tmp_name'] -> string

并尝试做

$copied = copy("Array['tmp_name']" ....);

在任何情况下，您都应该使用move_uploaded_file（）来处理移动的上传文件，而不是copy()。 m_u_l有额外的检查，以确保在上传完成和脚本试图移动之间没有人篡改文件。

Answer 5

以上内容都无法解决我的问题。实际上，目录和文件对用户php（=='www-data'）具有良好的权利。但是

dump(exec("whoami")); // returns 'another'

帮助确定php用户不是等待已久的用户（“ www-data”），而是“另一个”。

某些程序已编辑/ etc / apache2 / envvars

export APACHE_RUN_USER=another
export APACHE_RUN_GROUP=another

取回www-data

export APACHE_RUN_USER=www-data
export APACHE_RUN_GROUP=www-data

重新启动apache可以解决所有问题。

sudo service apache2 restart

希望有所帮助

php复制功能，无法打开流：权限被拒绝

5 个答案: