Question

我是Java领域的新手。

我想在调用参数时丢失错误并从正文中获取错误消息（例如，标题）。但是我不能。

我附加了我的全部代码，在MovieListController.java文件中，我使用if / else条件语句来引发异常。

实际上，我对Java还没有太多的了解。因此，请让我知道我应该修改或补充哪些部分。

谢谢。

我正在使用带有Spring-boot v2.1.4和Maven构建的eclipse 2019-03。

MovieList.java

package movie;

public class MovieList {

    private final long year;
    private final String title;

    public String getTitle() {
        return title;
    }

    public long getYear() {
        return year;
    }

    public MovieList( long year, String title) {
        this.title = title;
        this.year = year;
    }
}

MovieListController.java

package movie;

import org.springframework.web.bind.annotation.RequestHeader;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.RequestParam;
import org.springframework.web.bind.annotation.RestController;

@RestController
public class MovieListController {

    private static final String template = "The movie - %s ( %d )";

    @RequestMapping(value="/movielist", method=RequestMethod.GET)
    public MovieList movie(
            @RequestParam(value="title") String title,
            @RequestParam(value="year") long year,
            @RequestHeader(value="test") String header
            ) {
        if(title == null) {
            throw new MyException("test execution");
        } else {
            return new MovieList( year, String.format(template, title, year));
        }
    }
}

包含主要功能的Application.java

package movie;

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;

@SpringBootApplication
public class Application {

    public static void main(String[] args) {
        SpringApplication.run(Application.class, args);
    }

}

MyException.java

package movie;

import org.springframework.http.HttpStatus;
import org.springframework.web.bind.annotation.ResponseStatus;

@ResponseStatus(HttpStatus.BAD_REQUEST)
public class MyException extends RuntimeException {
    private static final long serialVersionUID = 1L;

    public MyException(String msg) {
        super(msg);
    }
}

即使在所需条件下也看不到任何异常消息

0 个答案: