JS：在命名函数内调用函数

Question

我正在尝试从create函数访问命名函数testingSounder。当它们嵌套这样的命名函数时，我将如何处理？

loadSounder: function() {
     var mentForm = (function (appId, locId) {
          var create = function() {
              console.log("CREATING")

          }
     })
},

testingSounder: function() {

     //How can I run the create function from loadSounder?
}

Answer 1

您需要返回两个函数：

loadSounder: function() {
     var mentForm = function (appId, locId) {
          var create = function() {
              console.log("CREATING")
          };
          return create;
     };
     return mentForm;
},

testingSounder: function() {
    this.loadSounder()("app", "loc")();
}