Question

I am using RestSharp to make a POST request containing a JSON body. But I get a Bad request error.

Because I have [] and "" in my JSON I have decided to use Newtonsoft.Json . Before using this I couldn't even see a JSON request being formed.

I am willing to try MS httpwebrequest as an alternative.

restClient = new RestClient();

restRequest = new RestRequest(ApiUrl, Method.POST, DataFormat.Json);

var myObject = "{ \"target\" : \"[5,5]\", \"lastseen\" : \"1555459984\" }";

var json = JsonConvert.SerializeObject(myObject);
restRequest.AddParameter("application/json", ParameterType.RequestBody);

restRequest.AddJsonBody(json);

Please note that I am trying to convert a JSON curl to C#. Please see below:

curl -H 'Content-Type: application/json' -X POST -d '{ "target" : [5, 5], "lastseen" : "1555459984", "previousTargets" : [ [1, 0], [2, 2], [2, 3] ] }' http://santized/santized/santized

Answer 1

You appear to be over serializing the data to be sent.

Consider creating an object and then passing it to AddJsonBody.

//...

restClient = new RestClient();

restRequest = new RestRequest(ApiUrl, Method.POST, DataFormat.Json);

var myObject = new { 
    target = new []{ 5, 5 }, 
    lastseen = "1555459984",
    previousTargets = new []{
        new [] { 1, 0 }, 
        new [] { 2, 2 }, 
        new [] { 2, 3 } 
    }
};

restRequest.AddJsonBody(myObject); //this will serialize the object and set header

//...

AddJsonBody sets content type to application/json and serializes the object to a JSON string.

Answer 2

Why not just this?

restClient = new RestClient();

restRequest = new RestRequest(ApiUrl, Method.POST, DataFormat.Json);

var myObject = "{ \"target\" : \"[5,5]\", \"lastseen\" : \"1555459984\" }";

restRequest.AddParameter("application/json", ParameterType.RequestBody);

restRequest.AddJsonBody(json);

Removed the line where you are serializing a json string.

Answer 3

您还可以使用：

public class RootObject
{
    public string target { get; set; }
    public string lastseen { get; set; }
}

restClient = new RestClient();

restRequest = new RestRequest(ApiUrl, Method.POST, DataFormat.Json);

RootObject myObject = new RootObject();
myObject.target = "[5,5]";
myObject.lastseen = "1555459984";
var json = JsonConvert.SerializeObject(myObject);

restRequest.AddParameter("application/json", ParameterType.RequestBody);

restRequest.AddJsonBody(json);

Answer 4

您可以执行以下示例：

  public static IRestRequest PostInformationAndPassToken(JsonObject tokenString, string path, string whatistobePosted)
    {
        IRestRequest request = new RestRequest(path, Method.POST);
        request.AddHeader("Authorization", $"Bearer {tokenString["Token"]}");
        request.AddHeader("cache-control", "no-cache");
        request.AddHeader("Content-Type", "application/json");
        request.AddParameter(whatistobePosted, ParameterType.RequestBody); 
        return request;
    }

Bad request encountered with RestSharp JSON POST request

4 个答案: