Question

我正在尝试在我的一个项目中设置事件，侦听器和作业。如果删除了“ implements ShouldQueue”，该代码将能够运行。但是一旦我在Job类中包含了ShouldSoulQueue工具，它就会停止工作

我的EventServiceProvider


class EventServiceProvider extends ServiceProvider
{

    protected $listen = [
        Registered::class => [
            SendEmailVerificationNotification::class,
        ],
        'App\Events\IncorpPaid' => [
            'App\Listeners\ProcessIncorpReceived',
        ],
    ];
}

我的活动课

Namespace App\Events;

use App\Company;
use Illuminate\Broadcasting\Channel;
use Illuminate\Queue\SerializesModels;
use Illuminate\Broadcasting\PrivateChannel;
use Illuminate\Broadcasting\PresenceChannel;
use Illuminate\Foundation\Events\Dispatchable;
use Illuminate\Broadcasting\InteractsWithSockets;
use Illuminate\Contracts\Broadcasting\ShouldBroadcast;

class IncorpPaid
{
    use Dispatchable, SerializesModels;

    /**
     * Create a new event instance.
     *
     * @return void
     */
    public function __construct(Company $company)
    {
        $this->company = $company;
    }

}

我的听众

namespace App\Listeners;

use App\Company;
use App\Events\IncorpPaid;
use Illuminate\Queue\InteractsWithQueue;
use Illuminate\Contracts\Queue\ShouldQueue;
use Illuminate\Http\Request;
use Illuminate\Queue\SerializesModels;

class ProcessIncorpReceived
{

    //use SerializesModels;
    /**
     * Create the event listener.
     *
     * @return void
     */
    public function __construct()
    {

    }

    /**
     * Handle the event.
     *
     * @param  IncorpPaid  $event
     * @return void
     */
    public function handle(IncorpPaid $event)
    {
        \App\Jobs\SendKYC::dispatch($event->company);
    }
}

最后是我的问题代码。

以下作品。但是问题在于使用这种方法不会使作业排队。

namespace App\Jobs;

use App\Company;
use Illuminate\Bus\Queueable;
use Illuminate\Queue\SerializesModels;
use Illuminate\Queue\InteractsWithQueue;
use Illuminate\Contracts\Queue\ShouldQueue;
use Illuminate\Foundation\Bus\Dispatchable;

class SendKYC
{
    use Dispatchable, InteractsWithQueue, Queueable, SerializesModels;

    /**
     * Create a new job instance.
     *
     * @return void
     */
    public function __construct(Company $company)
    {
        $this->company = $company;
    }

    /**
     * Execute the job.
     *
     * @return void
     */
    public function handle(Company $company)
    {
        //error_log(print_r($this->company->puc,true));
    //  error_log(print_r($company,true));
        \App\Services\SendDocsForSignature::processKYC($this->company);
    }
}

但是，这使作业排队，但不起作用。 $ this-> company返回一个空白的公司模型。

namespace App\Jobs;

use App\Company;
use Illuminate\Bus\Queueable;
use Illuminate\Queue\SerializesModels;
use Illuminate\Queue\InteractsWithQueue;
use Illuminate\Contracts\Queue\ShouldQueue;
use Illuminate\Foundation\Bus\Dispatchable;

class SendKYC implements ShouldQueue
{
    use Dispatchable, InteractsWithQueue, Queueable, SerializesModels;

    /**
     * Create a new job instance.
     *
     * @return void
     */
    public function __construct(Company $company)
    {
        $this->company = $company;
    }

    /**
     * Execute the job.
     *
     * @return void
     */
    public function handle(Company $company)
    {
        \App\Services\SendDocsForSignature::processKYC($this->company);
    }
}

Answer 1

您的最后一个代码段看起来几乎正确。您只需要声明要在其中存储$company值的实例变量。换句话说，您需要将protected $company;添加到SendKYC类中，才能将$company的值分配给$this->company。

您SendKYC的课程应该这样开始：

class SendKYC implements ShouldQueue
{
    use Dispatchable, InteractsWithQueue, Queueable, SerializesModels;

    protected $company;

    /**
     * Create a new job instance.
     *
     * @return void
     */
    public function __construct(Company $company)
    {
        $this->company = $company;
    }

Laravel无法处理队列模型，但是能够在没有队列的情况下处理代码

1 个答案: