Question

我正在使用带有SPring数据的spring-boot，并且只是试图通过命令行创建一个简单的用户名创建方法，并使用哈希密码将密码发送给db。

我收到此错误，并说我的服务为空？当我查看如何传递我的价值观时，无论如何它们似乎都传递了正确的价值观。我只是不知道在何处以及为什么它会显示空指针异常，而我的JPA回购保存功能一直都在接收适当的属性。

我的实体是..

 @Entity
 @EntityScan
 public class Users {


@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private int id;

@Column
private String username;
@Column
private String password;


@Override
public String toString() {
    return new StringJoiner(", ", Users.class.getSimpleName() + "[", "]")
            .add("id=" + id)
            .add("username='" + username + "'")
            .add("password='" + password + "'")
            .toString();
}

public int getId() {
    return id;
}
public void setId(int id) {
    this.id = id;
}
public String getUsername() {
    return username;
}
public void setUsername(String username) {
    this.username = username;
}

public String getPassword() {
    return password;
}

public void setPassword(String password) {
    this.password = password;
}
}

我的主要课程是

@SpringBootApplication
public class HashingexerApplication {

    @Autowired
    UserService userService;

    public static void main(String[] args) {
        SpringApplication.run(HashingexerApplication.class, args);
//        Scanner input=new Scanner(System.in);
        String username, password;
        System.out.println("Enter a username: ");
//    username = input.nextLine();
        username = "josh";
        System.out.println("Enter a password: ");
//    password = input.nextLine();
        password = "pass";
        String salt = "_Hello_World";
        System.out.println("Password before encryption: " + password);
        System.out.println("Salt to be added is: " + salt);
        String saltedPass = password + salt;
        System.out.println("Unencrypted Salted Password is: " + password + salt);
        String passwordEncrypt = BCrypt.hashpw(password, BCrypt.gensalt(12));
        System.out.println("Encrypted Salted Password is: " + passwordEncrypt);
        Users users = new Users();
        users.setId(1);
        users.setUsername(username);
        users.setPassword(passwordEncrypt);
        System.out.println("Object:: " + users);
        HashingexerApplication d = new HashingexerApplication();
        d.save(users);
    }
    public String save(Users users) {
        System.out.println("method: " + users);
        userService.save(users);
        return "Done";
    }
}

错误详细信息：

线程“ restartedMain”中的异常 java.lang.reflect.InvocationTargetException在 sun.reflect.NativeMethodAccessorImpl.invoke0（本机方法）位于 sun.reflect.NativeMethodAccessorImpl.invoke（NativeMethodAccessorImpl.java:62）在 sun.reflect.DelegatingMethodAccessorImpl.invoke（DelegatingMethodAccessorImpl.java:43）在java.lang.reflect.Method.invoke（Method.java:498）在 org.springframework.boot.devtools.restart.RestartLauncher.run（RestartLauncher.java:49）由以下原因引起：java.lang.NullPointerException hashingexer.hashingexer.HashingexerApplication.save（HashingexerApplication.java:61）在 hashingexer.hashingexer.HashingexerApplication.main（HashingexerApplication.java:51） ...还有5个

Answer 1

这将为您提供帮助

<dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-devtools</artifactId>
            <optional>true</optional>
        </dependency>
        <dependency>
            <groupId>org.springframework</groupId>
            <artifactId>spring-test</artifactId>
            <version>5.0.4.RELEASE</version>
  </dependency>

线程“ restartedMain”中的异常java.lang.reflect.InvocationTargetException ....由以下原因引起：java.lang.NullPointerException

1 个答案: