如何在Spring数据中编写替换根和合并对象聚合操作

时间:2019-04-16 03:44:13

标签: mongodb spring-boot spring-data aggregation-framework

我编写了一个MongoDB本机查询,该查询可以正常工作。我正在尝试编写等效于Spring数据的查询,但无法这样做。基本上,我想根据输入数组中提供的标题过滤掉字段数组。这是示例文档:

{
   "domain":"diageotest.com",
   "locale":"en-gb",
   "pageName":"Content_1",
   "contents":[
      {
         "contentName":"Template_1",
         "fields":[
            {

               "id":"firstname",
               "fieldType":"Plain Text",
               "title":"First Name",
               "value":"Pawan"
            },
            {             
               "id":"lastname",
               "fieldType":"Plain Text",
               "title":"Last Name",
               "value":"Kumar"
            }
         ]
      }
   ],
   "createdBy":"ag-KumarJog",
   "createdDate":"Jan 23,2019",
   "isDefaultLocale":true,
   "modifiedBy":"ag-KumarJog",
   "modifiedDate":"Jan 23,2019",
   "version":1
}

以下是我的本机查询:

db.contents.aggregate([ 
                {$match: { $and: [
                                {"domain": "diageotest.com"},
                                {"locale": {$in: ["en-in", "en-us"]}},
                                {"contents.contentName": "Template_1"}
                                ]
                                                }
                }, 
                {$unwind: "$contents"}, 
                {$unwind: "$contents.fields"}, 
                {$match: { "contents.fields.title": {$in: ["First Name"]}}}, 
                {$group: { "_id": "$_id", 
                           "contents":  { "$push": "$contents"}, 
                           "root": {$first:"$$ROOT"} }}, 
                {$replaceRoot:{newRoot:{$mergeObjects:["$root",{contents:'$contents'}]}}},
                {$skip : 0},
                {$limit : 5}
                ]);

在这里,在上面的查询中,如果我在数组中传递“名字”(条件为$),则输出JSON将仅包含标题为“名字”的字段。

在Java中,我尝试在下面尝试,但卡在替换根目录上:

MatchOperation matchOperation = this.matchByTemplateDomainAndLocales(domainName, templateName,
                requestBody.getLocales());
// ---------------------------------------------------//
UnwindOperation unwindContents = unwind("$contents");
UnwindOperation unwindFields = unwind("$contents.fields");
MatchOperation matchFields = match(where("contents.fields.title").in(requestBody.getFields()));
GroupOperation groupOperation = group("id").push("$contents").as("contents").first("$$ROOT").as("root");
//ReplaceRootOperation replaceRootOperation = builder().withDocument()
// ---------------------------------------------------//
SortOperation sortOperation = sort(sort);
LimitOperation limitOperation = limit(requestBody.getLimit());
SkipOperation skipOperation = skip(requestBody.getSkip().longValue());

在替换接受数组并执行合并的root时,我找不到合适的方法。请帮助。

1 个答案:

答案 0 :(得分:0)

如果您不想更改“内容”字段名称,可以使用:

ReplaceRootOperation operation = replaceRoot().withValueOf(ObjectOperators.valueOf("$root").mergeWith("$content"));

否则,不确定这是否是最干净的解决方案,但您可以这样创建它:

Map<String, String> fieldMapping = new HashMap<>();
fieldMapping.put("content", "$content");
ReplaceRootOperation operation = replaceRoot().withValueOf(ObjectOperators.valueOf("$root").mergeWith(fieldMapping));