Question

此代码不使用错误处理即可正常运行。有没有更有效的方式来编写此代码？我很想向大家学习。

from getpass import getpass

username = input("Username: ")
grant_access = False

while not grant_access:
  password = getpass("Password: ")
  if password == 'pass123':
    grant_access = True
  elif password != 'pass123':
    while not grant_access:
      password = getpass("Re-enter Password: ")
      if password == 'pass123':
        grant_access = True
      elif password != 'pass123':
        continue

print("Logging in...")

Answer 1

您可以这样操作：

from getpass import getpass

username = input("Username: ")
password = getpass("Password: ")

if password != 'pass123':
  while True:
    password = getpass("Re-enter Password: ")
    if password == 'pass123':
      break

print("Logging in...")

甚至是这样：

from getpass import getpass

username = input("Username: ")
password = getpass("Password: ")

while password != 'pass123':
  password = getpass("Re-enter Password: ")

print("Logging in...")

请告诉我如何使此代码更“ Pythonic”

1 个答案: