Question

我创建了一个包含动作监听器的按钮。我在动作侦听器外部声明了变量。但是我不能在actionlistener中更改变量内容。我总是收到错误消息：从内部类引用的局部变量必须是final或有效的final

我该如何解决问题？

我希望代码部分对您足够好。

我已经尝试过：

final int player = 1;

但是我不能用final更改内容。

public void Game(char[] gamefield) { 
    int player = 1;
    TickTackToeSpieleablauf window = new TickTackToeSpieleablauf();
    btnSpielebrett1.addActionListener(new ActionListener() {
        @Override
        public void actionPerformed(ActionEvent e) {
           //Field1
           int field = 0;
           boolean geklappt = false;
           geklappt = window.playervsplayer(gamefield, field, player);
           System.out.println(gamefield[0]);
           if (geklappt && player == 1){
               gamefield[field] = 'x';
               player = 2; <----- HERE I GET THE ERROR
           }else if(geklappt && player == 2){
               gamefield[field] = 'o';
           }else if(!geklappt){
                if (gamefield[0] != '1' && gamefield[1] != '2' &&gamefield[2] != '3' && gamefield[3] != '4' &&gamefield[4] != '5' && gamefield[5] != '6' &&gamefield[6] != '7' && gamefield[7] != '8' &&gamefield[8] != '9'){
                    //Gamefield full, array clear;
                        gamefield[0] = '1';
                        gamefield[1] = '2';
                        gamefield[2] = '3';
                        gamefield[3] = '4';
                        gamefield[4] = '5';
                        gamefield[5] = '6';
                        gamefield[6] = '7';
                        gamefield[7] = '8';
                        gamefield[8] = '9';
                }
           }else{
               System.out.println("Feld bereits belegt.");
           }
}

Answer 1

Ypu可以为您的player值提供包装类，例如：

class Player {
    int value = 1;
}

并使用对此类的引用而不是原始类型：

final Player player = new Player();

...

if (geklappt && player.value == 1){
      gamefield[field] = 'x';
      player.value = 2;
}

在actionlistener中更改变量数据

1 个答案: