Question

我有一个表，其中包含ID，描述和代码列。我需要使用描述列来填充代码列。样本描述为“调查和补救措施”，因此我的代码应为“ IRM”。

注意：是否有诸如“ and / for / to / to / in”之类的词避免使用

Answer 1

此代码可以为您提供帮助。

 declare @input as varchar(1000) -- Choose the appropriate size
  declare @output as varchar(1000) -- Choose the appropriate size

 select @input = 'Investigations and Remedial Measures', @output = ''

 declare @i int

select @i = 0

while @i < len(@input)
begin
select @i = @i + 1

select @output = @output +  case when  unicode(substring(@input, @i, 1))between 65 
   and 90 then substring(@input, @i, 1)  else '' end

end

SELECT @output

Answer 2

我个人将使用内联表值函数

在SQL Server 2017或更高版本或Azure SQL数据库上：

CREATE OR ALTER FUNCTION dbo.ExtractUpperCase(@s nvarchar(4000))
RETURNS TABLE
WITH SCHEMABINDING
AS
  RETURN 
  (
    WITH s(s) AS (SELECT 1 UNION ALL SELECT s+1 FROM s WHERE s < LEN(@s))
    SELECT TOP (3) value = STRING_AGG(SUBSTRING(@s,s,1),'') 
      WITHIN GROUP (ORDER BY s.s) 
      FROM s WHERE ASCII(SUBSTRING(@s,s,1)) BETWEEN 65 AND 90
  );
GO

在SQL Server 2016或更早版本上：

CREATE FUNCTION dbo.ExtractUpperCase(@s nvarchar(4000))
RETURNS TABLE
WITH SCHEMABINDING
AS
  RETURN 
  (
    WITH s(s) AS (SELECT 1 UNION ALL SELECT s+1 FROM s WHERE s < LEN(@s))
    SELECT value = (SELECT TOP (3) v = SUBSTRING(@s,s,1) FROM s
      WHERE ASCII(SUBSTRING(@s,s,1)) BETWEEN 65 AND 90 
      ORDER BY s.s FOR XML PATH, TYPE).value(N'.[1]',N'nvarchar(4000)')
  );
GO

无论哪种情况：

CREATE TABLE #x(id int, name nvarchar(4000));

INSERT #x(id, name) VALUES
  (1, N'Belo Horizonte Orange'),
  (2, N'São Paulo Lala'),
  (3, N'Ferraz de Vasconcelos Toranto');

SELECT id, f.value FROM #x AS x
  CROSS APPLY dbo.ExtractUpperCase(x.name) AS f
  ORDER BY id OPTION (MAXRECURSION 4000);

结果：

id     name
----   ----
1      BHO
2      SPL
3      SVT

仅当您的字符串可以超过100个字符时，才需要OPTION (MAXRECURSION 4000)。

如何仅从给定值获得大写字母

2 个答案: