我有一个表,其中包含ID,描述和代码列。我需要使用描述列来填充代码列。样本描述为“调查和补救措施”,因此我的代码应为“ IRM”。
注意:是否有诸如“ and / for / to / to / in”之类的词避免使用
答案 0 :(得分:0)
此代码可以为您提供帮助。
declare @input as varchar(1000) -- Choose the appropriate size
declare @output as varchar(1000) -- Choose the appropriate size
select @input = 'Investigations and Remedial Measures', @output = ''
declare @i int
select @i = 0
while @i < len(@input)
begin
select @i = @i + 1
select @output = @output + case when unicode(substring(@input, @i, 1))between 65
and 90 then substring(@input, @i, 1) else '' end
end
SELECT @output
答案 1 :(得分:0)
我个人将使用内联表值函数
在SQL Server 2017或更高版本或Azure SQL数据库上:
CREATE OR ALTER FUNCTION dbo.ExtractUpperCase(@s nvarchar(4000))
RETURNS TABLE
WITH SCHEMABINDING
AS
RETURN
(
WITH s(s) AS (SELECT 1 UNION ALL SELECT s+1 FROM s WHERE s < LEN(@s))
SELECT TOP (3) value = STRING_AGG(SUBSTRING(@s,s,1),'')
WITHIN GROUP (ORDER BY s.s)
FROM s WHERE ASCII(SUBSTRING(@s,s,1)) BETWEEN 65 AND 90
);
GO
在SQL Server 2016或更早版本上:
CREATE FUNCTION dbo.ExtractUpperCase(@s nvarchar(4000))
RETURNS TABLE
WITH SCHEMABINDING
AS
RETURN
(
WITH s(s) AS (SELECT 1 UNION ALL SELECT s+1 FROM s WHERE s < LEN(@s))
SELECT value = (SELECT TOP (3) v = SUBSTRING(@s,s,1) FROM s
WHERE ASCII(SUBSTRING(@s,s,1)) BETWEEN 65 AND 90
ORDER BY s.s FOR XML PATH, TYPE).value(N'.[1]',N'nvarchar(4000)')
);
GO
无论哪种情况:
CREATE TABLE #x(id int, name nvarchar(4000));
INSERT #x(id, name) VALUES
(1, N'Belo Horizonte Orange'),
(2, N'São Paulo Lala'),
(3, N'Ferraz de Vasconcelos Toranto');
SELECT id, f.value FROM #x AS x
CROSS APPLY dbo.ExtractUpperCase(x.name) AS f
ORDER BY id OPTION (MAXRECURSION 4000);
结果:
id name
---- ----
1 BHO
2 SPL
3 SVT
仅当您的字符串可以超过100个字符时,才需要OPTION (MAXRECURSION 4000)
。