比方说,我有一个简单的polar chart
:
R代码:
library(plotly)
p <- plot_ly(
type = 'scatterpolar',
r = c(0,1,2,4),
theta = c(0,45,90,120),
size = c(10, 20, 30, 40),
sizes = c(100, 300),
mode = 'markers'
) %>%
layout(
showlegend = FALSE,
polar = list(
angularaxis = list(
showticklabels = TRUE#,
#tickmode="array",
#tickvals = c(22.5, 67.5, 112, 157.5, 202, 247.5, 292, 337.5),
#ticktext = c('A', "B", "C", "D", "E", "F", "G", "H")
),
radialaxis = list(
tickmode="array",
tickvals = c(0, 1, 2, 3, 4, 5, 6, 7),
ticktext = c('', "One", "Two", "Three", "Four", "Five", "Six", "Seven")
)
)
)
ggplotly(p)
设置showticklabels = FALSE
时,角度刻度标签消失,然后我想将A,B,C,D,E,F,G and H
放置在角度c(22.5, 67.5, 112, 157.5, 202, 247.5, 292, 337.5)
上。
我无法使用ticktexts
和tickvals
得到下面的预期图。
有人可以帮我解决问题,还是可以使用add_text
或add_annotation
吗?
预期地积:
答案 0 :(得分:1)
您可以使用angularaxis
删除showgrid = FALSE
中的所有网格线,也可以每22.5度有一条从0开始的网格线,然后ticktext
就像这样{ {1}},也可以繁琐地添加期望的行,然后删除网格线,如下所示:
c('', 'A', '', 'B', '', 'C', .......)
输出图表:
我注意到,您在那里的预期输出会在您的代码中以相反的方式列出字母。如果这也是您需要的,只需更改字母的顺序以匹配这样的角度p <- plot_ly() %>%
# data points
add_trace(type = 'scatterpolar',
r = c(0,1,2,4),
theta = c(0,45,90,120),
size = c(10, 20, 30, 40),
sizes = c(100, 300),
mode = 'markers') %>%
# straight line from 0 dg to 180 dg
add_trace(type = 'scatterpolar',
r = c(0,4.3,4.3),
theta = c(0, 180, 360),
mode = 'lines',
line = list(color = 'grey', width = 1)) %>%
# straight line from 45 dg to 225 dg
add_trace(type = 'scatterpolar',
r = c(0,4.3,4.3),
theta = c(0, 45, 225),
mode = 'lines',
line = list(color = 'grey', width = 1)) %>%
# straight line from 90 dg to 270 dg
add_trace(type = 'scatterpolar',
r = c(0,4.3,4.3),
theta = c(0, 90, 270),
mode = 'lines',
line = list(color = 'grey', width = 1)) %>%
# straight line from 135 dg to 315 dg
add_trace(type = 'scatterpolar',
r = c(0,4.3,4.3),
theta = c(0, 135, 315),
mode = 'lines',
line = list(color = 'grey', width = 1)) %>%
# fill circle of radius 1
add_trace(type = 'scatterpolar',
mode = 'lines',
r = 1,
theta =seq(0, 360, 0.1),
line = list(color = 'grey'),
fill = 'toself',
fillcolor = 'grey',
opacity = 0.5) %>%
layout(
showlegend = FALSE,
polar = list(
angularaxis = list(
showticklabels = TRUE,
# remove grid lines and ticks
showgrid = FALSE,
ticks = '',
# if you want the axis to go the other way around
# direction = 'clockwise',
tickmode="array",
tickvals = seq(22.5, 337.5, 45),
ticktext = LETTERS[1:8]
),
radialaxis = list(
tickmode="array",
tickvals = c(0, 1, 2, 3, 4, 5, 6, 7),
ticktext = c('', "One", "Two", "Three", "Four", "Five", "Six", "Seven")
)
)
)
ggplotly(p)
(从c("A", "H", "G", "F", "E", "D", "C", "B")
开始的相反顺序)