Question

嗨，我正在尝试从所拥有的JSON格式中获取特定数据。我在练习中使用的是预制的json。

JSON格式是这样的：

[
{
"userId": 1,
"id": 1,
"title": "sunt aut facere repellat provident occaecati excepturi optio 
 reprehenderit",
"body": "quia et suscipit\nsuscipit recusandae consequuntur expedita et 
cum\nreprehenderit molestiae ut ut quas totam\nnostrum rerum est autem sunt   
rem eveniet architecto"
},
{
"userId": 1,
"id": 2,
"title": "qui est esse",
"body": "est rerum tempore vitae\nsequi sint nihil reprehenderit dolor 
beatae ea dolores neque\nfugiat blanditiis voluptate porro vel nihil 
molestiae 
ut reiciendis\nqui aperiam non debitis possimus qui neque nisi nulla"
},
{
"userId": 1,
"id": 3,
"title": "ea molestias quasi exercitationem repellat qui ipsa sit aut",
"body": "et iusto sed quo iure\nvoluptatem occaecati omnis eligendi aut 
ad\nvoluptatem doloribus vel accusantium quis pariatur\nmolestiae porro eius 
odio et labore et velit aut"
}
]

以此类推...

所以我要做的是从每个对象中获取标题数组。

这是我的代码：

<?php
$url = "https://jsonplaceholder.typicode.com/posts" ;
//  Initiate curl
$ch = curl_init() ;
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 
$result = curl_exec($ch) ;
curl_close($ch) ;

$data = json_decode($result);

foreach ($data as $datavalue) {
echo $datavalue->title;
echo "<br/>" ;
}

现在我要显示的是特定对象的标题，比如说用户ID = 2。

我该如何说服。请帮助我的查询。任何帮助都非常感谢。

Answer 1

您可以在循环中添加条件以检查想要的行，当找到时，可以将其存储在这样的变量中：

<?php


  $data = json_decode($result);

  $data = json_decode($result);

  $userId = 1;

  $result = null;

  foreach ($data as $datavalue) {
    echo $datavalue->title;
    if ($datavalue->userId == $userId) {
       $result = $datavalue;
       break;
    }
    echo "<br/>" ;
  }

var_dump($result); // if you want to display the title you can simply do $result->title but remember to check if $result is not null

Answer 2

您可以使用以下内容：

$id = 2;
getTitle($data, $id);

function getTitle($data = null, $id = null)
{
    foreach ($data as $datavalue) {
        if ($datavalue->id == $id) {
            echo $datavalue->title;
            echo "<br/>";
        }
    }
}

Answer 3

您可以使用php array_filter()函数。

//Your test data
$data = "[{\"userId\": 2,\"id\": 1,\"title\": \"sunt aut facere repellat provident occaecati excepturi optio reprehenderit\",\"body\": \"quia et suscipitsuscipit recusandae consequuntur expedita et cumreprehenderit molestiae ut ut quas totamnostrum rerum est autem sunt rem eveniet architecto\"},{\"userId\": 1,\"id\": 2,\"title\": \"qui est esse\",\"body\": \"est rerum tempore vitaesequi sint nihil reprehenderit dolor beatae ea dolores nequefugiat blanditiis voluptate porro vel nihil molestiae ut reiciendisqui aperiam non debitis possimus qui neque nisi nulla\"},{\"userId\": 1,\"id\": 3,\"title\": \"ea molestias quasi exercitationem repellat qui ipsa sit aut\",\"body\": \"et iusto sed quo iurevoluptatem occaecati omnis eligendi aut advoluptatemdoloribus vel accusantium quis pariaturmolestiae porro eius odio et labore et velit aut\"}]";

//Decode the data to a PHP array rather than object
$data = json_decode( $data, true );

const searchKey  = "userId";
const searchTerm = 2;

//Filter that array
$data = array_filter( $data, function( $value ){
    //If the value in the searched key matches the value, return true
    if( $value[ searchKey ] === searchTerm ){
        return true;
    } else {
        return false;
    }
});

您会看到我正在使用两个const和searchKey两个变量，您可以将它们更改为您希望在PHP {{1}中搜索的值}功能。

以下是有关PHP searchTerm函数的一些文档，您可能会觉得有用

https://www.php.net/manual/en/function.array-filter.php

JSON：使用php

3 个答案: