使用PHP检测纯文本格式的表情符号

Question

我想以以下形式更改表达式：

[E-01] - [E-02] - [E-03] - [E-04] ... 

到

<img src = "E-XX.png">

我该怎么做？

输入

$message = "Hello [E-02] World [E-01]";

所需的输出

Hello <img src="E-02.png"> World <img src="E-01.png">

Answer 1

Preg_replace是您的朋友：

$message = "Hello [E-02] World [E-01]";
$replaced = preg_replace('/\[(E-\d\d)\]/', '<img src="/assets/images/emoji/$1.png" height="20" width="20" />', $message);
echo $replaced;

输出：

Hello <img src="/assets/images/emoji/E-02.png" height="20" width="20" /> World <img src="/assets/images/emoji/E-01.png" height="20" width="20" />

Answer 2

function emoji($message){
            for($e=1; $e <= 60; $e++){
                $e    = (($e < 10) ? '0' . $e : $e);
                $name = 'E-' . $e;
                $message = str_replace('[' . $name . ']', ' <img src="/assets/images/emoji/' . $name. '.png" height="20" width="20" /> ', $message);
            }
            return $message;
        }