尝试使用对象的2个嵌套属性对数组进行分组。以下是我正在使用的数据。
我需要使用嵌套在start对象中的end和time属性对这些数据进行分组
`
[{
"id": 227,
"day": 0,
"time": {
"id": 31,
"start": "03:00:00",
"end": "06:00:00"
},
"max_tasks": 3
}, {
"id": 228,
"day": 1,
"time": {
"id": 31,
"start": "03:00:00",
"end": "06:00:00"
},
"max_tasks": 3
}, {
"id": 229,
"day": 2,
"time": {
"id": 31,
"start": "03:00:00",
"end": "06:00:00"
},
"max_tasks": 3
}, {
"id": 230,
"day": 3,
"time": {
"id": 31,
"start": "03:00:00",
"end": "06:00:00"
},
"max_tasks": 3
}, {
"id": 231,
"day": 4,
"time": {
"id": 31,
"start": "03:00:00",
"end": "06:00:00"
},
"max_tasks": 3
}, {
"id": 232,
"day": 5,
"time": {
"id": 31,
"start": "03:00:00",
"end": "06:00:00"
},
"max_tasks": 3
}, {
"id": 233,
"day": 6,
"time": {
"id": 31,
"start": "03:00:00",
"end": "06:00:00"
},
"max_tasks": 3
}, {
"id": 283,
"day": 0,
"time": {
"id": 39,
"start": "06:00:00",
"end": "08:00:00"
},
"max_tasks": 3
}, {
"id": 284,
"day": 1,
"time": {
"id": 39,
"start": "06:00:00",
"end": "08:00:00"
},
"max_tasks": 3
}, {
"id": 285,
"day": 2,
"time": {
"id": 39,
"start": "06:00:00",
"end": "08:00:00"
},
"max_tasks": 3
}, {
"id": 286,
"day": 3,
"time": {
"id": 39,
"start": "06:00:00",
"end": "08:00:00"
},
"max_tasks": 3
}, {
"id": 287,
"day": 4,
"time": {
"id": 39,
"start": "06:00:00",
"end": "08:00:00"
},
"max_tasks": 3
}, {
"id": 288,
"day": 5,
"time": {
"id": 39,
"start": "06:00:00",
"end": "08:00:00"
},
"max_tasks": 3
}, {
"id": 289,
"day": 6,
"time": {
"id": 39,
"start": "06:00:00",
"end": "08:00:00"
},
"max_tasks": 3
}]
`
当前，我可以使用以下代码使用一个属性进行分组，但不能同时使用这两个属性：
var result = _.groupBy(this.slots, 'time.start')
预期数据如下所示： `
03: 00: 00 - 06: 00: 00: [{
"id": 227,
"day": 0,
"time": {
"id": 31,
"start": "03:00:00",
"end": "06:00:00"
},
"max_tasks": 3
},
{
"id": 228,
"day": 1,
"time": {
"id": 31,
"start": "03:00:00",
"end": "06:00:00"
},
"max_tasks": 3
}
]
06: 00: 00 - 08: 00: 00: [{
"id": 283,
"day": 0,
"time": {
"id": 39,
"start": "06:00:00",
"end": "08:00:00"
},
"max_tasks": 3
},
{
"id": 284,
"day": 1,
"time": {
"id": 39,
"start": "06:00:00",
"end": "08:00:00"
},
"max_tasks": 3
}
]
`
预先感谢：）
答案 0 :(得分：2)
您可以使用函数library(tidyverse)
apollo_tbl <- read_csv("apollo.csv", col_names = TRUE)
plot1 <- ggplot(data = apollo_tbl, mapping = aes(x = covpercent, y = dayDifference)) +
geom_point() +
labs(x = "Cov Percent",
y = "Day Difference",
title = "Add your title here")
ggsave(filename = "apollo_scatter_plot", plot = plot1, device = "png" )
对这些值进行分组。
reducelet arr = [{ "id": 227, "day": 0, "time": { "id": 31, "start": "03:00:00", "end": "06:00:00" }, "max_tasks": 3}, { "id": 228, "day": 1, "time": { "id": 31, "start": "03:00:00", "end": "06:00:00" }, "max_tasks": 3}, { "id": 229, "day": 2, "time": { "id": 31, "start": "03:00:00", "end": "06:00:00" }, "max_tasks": 3}, { "id": 230, "day": 3, "time": { "id": 31, "start": "03:00:00", "end": "06:00:00" }, "max_tasks": 3}, { "id": 231, "day": 4, "time": { "id": 31, "start": "03:00:00", "end": "06:00:00" }, "max_tasks": 3}, { "id": 232, "day": 5, "time": { "id": 31, "start": "03:00:00", "end": "06:00:00" }, "max_tasks": 3}, { "id": 233, "day": 6, "time": { "id": 31, "start": "03:00:00", "end": "06:00:00" }, "max_tasks": 3}, { "id": 283, "day": 0, "time": { "id": 39, "start": "06:00:00", "end": "08:00:00" }, "max_tasks": 3}, { "id": 284, "day": 1, "time": { "id": 39, "start": "06:00:00", "end": "08:00:00" }, "max_tasks": 3}, { "id": 285, "day": 2, "time": { "id": 39, "start": "06:00:00", "end": "08:00:00" }, "max_tasks": 3}, { "id": 286, "day": 3, "time": { "id": 39, "start": "06:00:00", "end": "08:00:00" }, "max_tasks": 3}, { "id": 287, "day": 4, "time": { "id": 39, "start": "06:00:00", "end": "08:00:00" }, "max_tasks": 3}, { "id": 288, "day": 5, "time": { "id": 39, "start": "06:00:00", "end": "08:00:00" }, "max_tasks": 3}, { "id": 289, "day": 6, "time": { "id": 39, "start": "06:00:00", "end": "08:00:00" }, "max_tasks": 3}]
let result = arr.reduce((a, c) => {
let key = `${c.time.start} - ${c.time.end}`;
(a[key] || (a[key] = [])).push(c);
return a;
}, {});
console.log(result);
答案 1 :(得分：2)
将_.groupBy()与回调一起使用，并根据start和end生成密钥：
const data = [{"id":227,"day":0,"time":{"id":31,"start":"03:00:00","end":"06:00:00"},"max_tasks":3},{"id":228,"day":1,"time":{"id":31,"start":"03:00:00","end":"06:00:00"},"max_tasks":3},{"id":229,"day":2,"time":{"id":31,"start":"03:00:00","end":"06:00:00"},"max_tasks":3},{"id":230,"day":3,"time":{"id":31,"start":"03:00:00","end":"06:00:00"},"max_tasks":3},{"id":231,"day":4,"time":{"id":31,"start":"03:00:00","end":"06:00:00"},"max_tasks":3},{"id":232,"day":5,"time":{"id":31,"start":"03:00:00","end":"06:00:00"},"max_tasks":3},{"id":233,"day":6,"time":{"id":31,"start":"03:00:00","end":"06:00:00"},"max_tasks":3},{"id":283,"day":0,"time":{"id":39,"start":"06:00:00","end":"08:00:00"},"max_tasks":3},{"id":284,"day":1,"time":{"id":39,"start":"06:00:00","end":"08:00:00"},"max_tasks":3},{"id":285,"day":2,"time":{"id":39,"start":"06:00:00","end":"08:00:00"},"max_tasks":3},{"id":286,"day":3,"time":{"id":39,"start":"06:00:00","end":"08:00:00"},"max_tasks":3},{"id":287,"day":4,"time":{"id":39,"start":"06:00:00","end":"08:00:00"},"max_tasks":3},{"id":288,"day":5,"time":{"id":39,"start":"06:00:00","end":"08:00:00"},"max_tasks":3},{"id":289,"day":6,"time":{"id":39,"start":"06:00:00","end":"08:00:00"},"max_tasks":3}]
const result = _.groupBy(data, ({ time: { start, end } }) => `${start} - ${end}`)
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>