我创建了在选择值时自动添加价格的脚本。它正在工作,并且remove字段正在工作,但仅适用于“ li”字符串值。 我该怎么做,将“ li”连接到价格,然后按删除按钮以计算正确的价格。 例如,如果我将添加几个元素,并尝试删除第一个元素,它将删除正确的对象,但是价格将从最后一个元素中扣除。如何解决?谢谢
问题在里面
<!DOCTYPE html>
<html>
<body>
<p class="control-label col-xs-4">Ingridients</p>
<table>
<tr>
<div>
<input type="checkbox" id="coffee" name="coffee" checked>
<label for="coffee">Coffee</label>
</div>
</tr>
<tr>
<div>
<input type="checkbox" id="gym" name="gym">
<label for="gym">Gym</label>
</div>
</tr>
<tr>
<div>
<input type="checkbox" id="rose" name="rose">
<label for="rose">Rose</label>
</div>
</tr>
</table>
<select name="oil" id="oil">
<option value="avokado">Avokado</option>
<option value="kokos">Kokos</option>
<option value="vine">Vine</option>
</select>
</br>
<select name="color" id="color">
<option value="black">black</option>
<option value="white">white</option>
<option value="pink">pink</option>
</select>
</br>
<select name="smell" id="smell">
<option value="rose">rose</option>
<option value="kokos">Kokos</option>
<option value="gym">gym</option>
</select>
</br>
<button class="btn" style="float:right" onclick="myFunction()" type="button">Add</button>
<ul id="myList">
</ul>
<p id="price">Price : 0 pln</p>
<script>
var idtext = 0
var varprice = 0;
var dict = {};
function myFunction() {
var checkboxvalue = 0;
var node = document.createElement("LI");
var checkBoxCoffe = document.getElementById("coffee");
var checkBoxGym = document.getElementById("gym");
var checkBoxRose = document.getElementById("rose");
var textnode = document.createTextNode("");
var selectBoxOil = document.getElementById("oil");
var strOil = selectBoxOil.options[selectBoxOil.selectedIndex].text;
var selectBoxColor = document.getElementById("color");
var strColor = selectBoxColor.options[selectBoxColor.selectedIndex].text;
var selectBoxSmell = document.getElementById("smell");
var strSmell = selectBoxSmell.options[selectBoxSmell.selectedIndex].text;
if (checkBoxCoffe.checked == true) {
textnode.textContent = textnode.textContent + "Coffee; "
checkboxvalue = checkboxvalue + 1;
}
if (checkBoxGym.checked == true) {
textnode.textContent = textnode.textContent + "Gym; "
checkboxvalue = checkboxvalue + 1;
}
if (checkBoxRose.checked == true) {
textnode.textContent = textnode.textContent + "Rose; "
checkboxvalue = checkboxvalue + 1;
}
var button = document.createElement("button");
button.innerHTML = "Remove";
button.onclick = function() {
button.parentElement.remove()
varprice = varprice - dict[idtext];
document.getElementById("price").innerHTML = 'Price : ' + varprice + ' pln';
return;
};
idtext = idtext + 1
if (checkboxvalue == 1) {
dict[idtext] = 5;
} else if (checkboxvalue == 2) {
dict[idtext] = 7;
} else if (checkboxvalue == 3) {
dict[idtext] = 9;
}
varprice = varprice + dict[idtext];
textnode.id = idtext
textnode.textContent = "Bomb : \n" + strColor + "; " + strOil + " oil; " + "Smell: " + strSmell + " Ingridients : " + textnode.textContent + idtext + "value " + dict[idtext]
node.appendChild(textnode);
node.appendChild(button);
document.getElementById("myList").appendChild(node);
document.getElementById("price").innerHTML = 'Price : ' + varprice + ' pln';
}
</script>
</body>
</html>
因为它仅删除父对象。如何将其与价格联系起来?
答案 0 :(得分:0)
之后
B<String, Integer, Void> b = null;
A<String, Integer, String> a = b;
添加@objc func fetchDeviesNewDevice(){
let mainTableVC3 = DeviceTableViewCell()
mainTableVC3.newdevicechipnumber = self.newdevicechipnumber.text
mainTableVC3.buttonaktif()
....
}
更改
mainTableVC3.buttonaktif()
之后的mainTableVC3.buttonNew.isHidden = false
yourTableView.reloadData()
到android:usesCleartextTraffic="true"
<application
android:allowBackup="true"
android:icon="@mipmap/ic_launcher"
android:label="@string/app_name"
android:theme="@style/AppTheme"
android:usesCleartextTraffic="true">