我正在创建一个随机数生成器多人游戏（LAN）。 我需要有关如何创建代码的帮助，以使每个玩家都能收到自己的随机数，而且只要一个玩家猜出了一个密码，下一个回合就会是新玩家。与输出显示以下内容类似，
弗雷德，请猜测随机数（仅整数！）：5 太低
汤姆，请猜测随机数（仅整数！）：95 太高
John，请猜测随机数（仅整数！）：50 太低
然后，当一个玩家猜对了时，他们的回合将被跳过，并且当所有玩家都猜对了他们的号码后，游戏将结束，显示每个人都猜到的号码以及他们先前猜到的号码。 这是我到目前为止的内容：
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner keyboard = new Scanner(System.in);
Random myRand = new Random();
ArrayList<Integer> guessedNumbers = new ArrayList();
int x = 0;
int players = 0;
System.out.println("how many players are there?:");
players = checkint(players);
int arraySize = guessedNumbers.size();
int[] numPlayers = new int [players];
boolean play = true;
boolean validGuess = true;
String [] pNames = new String[players];
for (int i = 0; i<players; i++) {
System.out.println("New player, what is your name?:");
pNames[i] = keyboard.nextLine();
}
while(play) {
int randNum = myRand.nextInt(100) + 1;
int numOfGuesses = 0;
do {
System.out.println("Enter what you think the number is between 0 and 100!:");
x= checkint(x);
guessedNumbers.add(x);
if (x < 0) {
System.out.println("we don't accept negative numbers");
if (x > 100) {
System.out.println("that number is above the random number generator range");
}
}
numOfGuesses++;
if (x == randNum) {
System.out.println("that's correct!");
System.out.println("It took you " + numOfGuesses + " tries!");
System.out.print("these are all the numbers you guessed:");
for(int count=0; count<guessedNumbers.size(); count++){
System.out.print(guessedNumbers.get(count) + ",");}
System.out.println("");
boolean playError = true;
//if ("Yes".equals(answer)) {
do {
System.out.println("Would you like to play again: Yes or No");
String answer = keyboard.nextLine();
if (answer.compareToIgnoreCase("yes") == 0) {
play = true;
playError = false;
} else if (answer.compareToIgnoreCase("no") == 0) {
play =false;
playError = false;
System.out.println("Thank you for playing");
} else {
//you messed up
System.out.println("You answer was invalid");
playError = true;
}
} while (playError == true);
}
else if
(x>randNum)
System.out.println("Lower than that!");
else if
(x<randNum)
System.out.println("Higher than that!");
} while (x != randNum);
}}
}
static int checkint(int a) {
int enteredNumber = 0;
Scanner myScanner = new Scanner(System.in);
boolean numberError = false;
String enteredString = "";
do {
try {
enteredString = myScanner.next(); //Read into a string
enteredNumber = Integer.parseInt(enteredString.trim()); //then cast as a integer
numberError = false; //if we haven't bailed out, then the number must be valid.
} catch(Exception e) {
System.out.println("Your entry: \"" + enteredString + "\" is invalid...Please try again");
numberError = true; //Uh-Oh...We have a problem.
}
} while (numberError == true ); //Keep asking the user until the correct number is entered.
return enteredNumber;
}
}
答案 0 :(得分：0)
只需使用Random类：
s = MySequence()
for i in range(len(s)):
print s[i] # prints 1, then 2, then 3
for x in s:
print x # prints 1, then 2, then 3
print isinstance(s, collections.Sequence) # prints True
print 1 in s # prints True
print list(reversed(s)) # prints [3, 2, 1]
我在这里引用了。
How do I generate random integers within a specific range in Java?
答案 1 :(得分：0)
您正在以复杂的方式执行简单的操作，但是，我的代码仍可以由压缩版本代替，但是您可以更好地理解这一点。以下代码完全可以实现您想要的功能。我已经：
Player类，因此每个player都将记录guessedNumbers，Number of Guesses及其name。pName[]，play，validGuesses等... If-Conditions，并删除了外部的while-loop 更新的代码：现在，每个玩家都有不同的random number来猜测。
import java.util.*;
public class GuessNumber
{
public static void main(String[] args)
{
// TODO Auto-generated method stub
Scanner keyboard = new Scanner(System.in);
Random myRand = new Random();
ArrayList<Player> players = new ArrayList<Player>();
int x = 0;
System.out.println("how many players are there?:");
int noPlayer = checkint();
boolean validGuess = true , playError = true;
for (int i = 0; i<noPlayer; i++)
{
System.out.println("New player, what is your name?:");
players.add(new Player (keyboard.nextLine()));
}
for (int i = 0; i<noPlayer; i++)
{
players.get(i).number = myRand.nextInt(100) + 1;
}
int i =0; // for chossing different player each time
do
{
System.out.printf(players.get(i).name + " enter what you think the number is between 0 and 100!: ");
x= checkint();
players.get(i).guessedNumbers.add(x);
players.get(i).numOfGuesses++;
if (x == players.get(i).number)
{
System.out.println("That's correct!");
System.out.println("It took you " + players.get(i).numOfGuesses + " tries!");
System.out.print("These are all the numbers you guessed: ");
System.out.println(players.get(i).guessedNumbers);
do
{
System.out.println("Would you like to play again: Yes or No");
String answer = keyboard.nextLine();
if (answer.compareToIgnoreCase("yes") == 0)
{
playError = false;
players.get(i).number = myRand.nextInt(100) + 1; // creates a new random number for second round of the game
System.out.println("\n\n************ " +players.get(i).name + " WON ********");
System.out.println("\n************* SECOND ROUND STARTS **********");
}
else if (answer.compareToIgnoreCase("no") == 0)
{
playError = false;
System.out.println("Thank you for playing");
System.out.println("\n\n************ " +players.get(i).name + " WON ********");
System.out.println("\n************* SECOND ROUND STARTS **********");
players.remove(i);
}
else
{
System.out.println("You answer was invalid");
playError = true;
}
} while (playError);
}
else if (x>players.get(i).number)
System.out.println("Lower than that!");
else if (x<players.get(i).number)
System.out.println("Higher than that!");
if(i == noPlayer-1 || !(playError))
i = 0;
else
i++;
}while (players.size() > 0);
System.out.println("\n\n******************** Every Body Guessed Their Numbers ******************");
}
static int checkint()
{
int enteredNumber = 0;
Scanner myScanner = new Scanner(System.in);
boolean numberError = false;
do
{
try
{
enteredNumber = Integer.parseInt(myScanner.next().trim());
if (enteredNumber < 0 || enteredNumber > 100)
{
System.out.println("Either you entered a negative number or number is above the random number generator range");
numberError = true;
}
else
numberError = false; //if we haven't bailed out, then the number must be valid.
} catch(Exception e)
{
System.out.println("Your entry is invalid...Please try again");
numberError = true; //Uh-Oh...We have a problem.
}
} while (numberError); //Keep asking the user until the correct number is entered.
return enteredNumber;
}
}
// now each player would have its own record.
class Player
{
int numOfGuesses= 0;
ArrayList<Integer> guessedNumbers = new ArrayList<Integer>();
String name = "";
int number = 0;
public Player(String nam)
{
name = nam;
}
}
注意：：我已经添加了一些新行以在屏幕上输出，一旦有玩家wins并想再次玩就可以了。我建议您将您的代码与我的代码进行比较，以便对我的方法与我的代码有更好的了解。如果您发现难以理解的内容，请告诉我。