我正在制作一个按钮,它将在Python的tkinter模块中显示一条消息。
首先,按钮上有文字。单击后,将显示一个消息框。消息框是“弹出窗口”或“错误消息”。
下面的代码将显示执行上述语句的示例函数。
def joke1():
messagebox.showinfo(title = "There are three types of people in this world", message = "Those who can count and those who can't.")
root = Tk()
root.title("Joke Board 1.0 by Jamlandia")
root.iconbitmap(r"C:\Users\VMWZh\Downloads\Icons8-Ios7-Messaging-Lol.ico")
button = Button(text = "There are three types of people in this world", bg = '#42f474', fg = 'black', command = joke1)
test = Button()
button.grid(column = 0, row = 0)
test.grid(column = 1, row = 0)
root.mainloop()
我想不出一种方法来对其进行编码,因此当您按下按钮时,它将运行与按钮上显示的笑话相关的功能,然后将其随机绑定到一个新功能上,并将文本绑定到更改为与此功能相关的笑话。
答案 0 :(得分:0)
问题:按下按钮,...随机...开玩笑
random.randrange(start, stop[, step])
点击Joke
即可显示随机 Button
,而无需messagbox
。
import tkinter as tk
import random
class App(tk.Tk):
def __init__(self):
super().__init__()
self.joke_index = 0
self.jokes = [("There are three types of people in this world", "Those who can count and those who can't."),
('Grew up with six brothers', 'That’s how I learned to dance–waiting for the bathroom'),
('Always borrow money from a pessimist.', 'He won’t expect it back.')
]
self.label1 = tk.Label(self)
self.label1.grid(row=0, column=0, pady=3)
self.label2 = tk.Label(self)
self.label2.grid(row=1, column=0, pady=3)
button = tk.Button(self,
text='Show next Joke',
command=self.show_random_joke,
bg='#42f474', fg='black'
)
button.grid(row=2, column=0, pady=3)
def show_random_joke(self):
v = -1
while v == self.joke_index:
v = random.randrange(0, len(self.jokes)-1)
self.joke_index = v
self.label1['text'], self.label2['text'] = self.jokes[self.joke_index]
if __name__ == "__main__":
App().mainloop()
使用Python测试:3.5