request_people最初是'254,,one,one,one,99,,one,one,ORCHARD,one,ON,one/255,254,TWO,TWO,TWO,99'
,它转换为:
request_people
array(2): {
[0]: array(13): {
[0]: string(3): "254"
[1]: string(0): ""
[2]: string(3): "one"
[3]: string(3): "one"
[4]: string(3): "one"
[5]: string(2): "99"
[6]: string(0): ""
[7]: string(3): "one"
[8]: string(3): "one"
[9]: string(7): "ORCHARD"
[10]: string(3): "one"
[11]: string(2): "ON"
[12]: string(3): "one"
}
[1]: array(6): {
[0]: string(3): "255"
[1]: string(3): "254"
[2]: string(3): "TWO"
[3]: string(3): "TWO"
[4]: string(3): "TWO"
[5]: string(2): "99"
}
}
我想通过将索引的第一个元素转换为实际索引来重新定义数组。
因此输出应为:
new_request_people
array(2): {
[254]: array(12): {
[0]: string(0): ""
[1]: string(3): "one"
[2]: string(3): "one"
[3]: string(3): "one"
[4]: string(2): "99"
[5]: string(0): ""
[6]: string(3): "one"
[7]: string(3): "one"
[8]: string(7): "ORCHARD"
[9]: string(3): "one"
[10]: string(2): "ON"
[11]: string(3): "one"
}
[255]: array(5): {
[0]: string(3): "254"
[1]: string(3): "TWO"
[2]: string(3): "TWO"
[3]: string(3): "TWO"
[4]: string(2): "99"
}
}
我有以下代码:
request_people = request_people.split('/');
for (i = 0; i < request_people.length; i++)
{
request_people[i] = request_people[i].split(',');
}
//dump(request_people, 'alert');
var new_request_people = new Array();
for (i = 0; i < request_people.length; i++)
{
var key = parseInt(request_people[i][0]);
new_request_people[key] = request_people[i];
dump(new_request_people, 'alert');
}
请注意,它似乎使数组具有给定值(69)的大小,并在最后添加“ test”。
答案 0 :(得分:2)
您可以构建一个新数组,并将第一个值作为其余内部数组的索引。
结果是一个包含两个元素的稀疏数组。
.as-console-wrapper { max-height: 100% !important; top: 0; }
Sub FormatData()
Workbooks.Open FileName:="C:\Users\john.doe\Documents\scripts\apps\allow\Weekly_Cash_Trending"
Workbooks("Weekly_Cash_Trending.xlsx").Activate
Columns("C:C").Select
Selection.NumberFormat = "$#,##0"
Range("A1").Select
ActiveWorkbook.SaveAs FileName:="C:\Users\john.doe\Documents\scripts\apps\allow\Weekly_Cash_Trending"
End Sub