Question

使用此功能：

export const combineValidators = <Input extends { [P in keyof Input]: (val: string) => Err }, Err>(
  validators: Input
) => (values: { [P in keyof Input]?: unknown }): { [P in keyof Input]: Err } => {
  // Ignore implementation.
  return {} as { [P in keyof Input]: Err };
};

这种用法：

const validator = combineValidators({
  name: (val) => val ? undefined : 'error',
  email: (val) => val ? undefined : 'error'
});

const errors = validator({
  name: 'Lewis',
  email: 'lewis@mercedes.com'
});

我希望TypeScript能够将返回类型推断为：

// Expected: `errors` to be inferred as:
interface Ret {
  name: string | undefined;
  email: string | undefined;
}

但是可以推断为：

// Actual: `errors` inferred as:
interface Ret {
  name: {};
  email: {};
}

我创建了一个live example in the TypeScript playground来演示此问题。

有人可以帮忙吗？

Answer 1

Err不会以您期望的方式进行推断。使用ReturnType条件类型从Input中提取返回类型可能更简单：

type ReturnTypes<T extends Record<keyof T, (...a: any[]) => any>> = {
  [P in keyof T]: ReturnType<T[P]>
}

export const combineValidators = <Input extends Record<keyof Input, (val: unknown) => any>>(
  validators: Input
) => (values: Record<keyof Input, unknown>): ReturnTypes<Input> => {
  return {} as ReturnTypes<Input>;
};

const validator = combineValidators({
  name: (val) => val ? undefined : 'error',
  email: (val) => val ? undefined : 'error'
});

const errors = validator({
  name: 'Lewis',
  email: 'lewis@mercedes.com'
});

我们甚至可以走得更远，如果您在验证函数中指定参数类型，则可以对传递给validator的对象的字段进行类型检查：

type ParamTypes<T extends Record<keyof T, (a: any) => any>> = {
  [P in keyof T]: Parameters<T[P]>[0]
}

type ReturnTypes<T extends Record<keyof T, (...a: any[]) => any>> = {
  [P in keyof T]: ReturnType<T[P]>
}

export const combineValidators = <Input extends Record<keyof Input, (val: unknown) => any>>(
  validators: Input
) => (values: ParamTypes<Input>): ReturnTypes<Input> => {
  return {} as ReturnTypes<Input>;
};

const validator = combineValidators({
  name: (val: string) => val ? undefined : 'error',
  email: (val) => val ? undefined : 'error', // if we leave it out, we still get unknown
  age: (val: number) => val ? undefined : 'error'
});

const errors = validator({
  name: 'Lewis',
  email: 'lewis@mercedes.com',
  age: 0
});

const errors2 = validator({
  name: 'Lewis',
  email: 'lewis@mercedes.com',
  age: "0" // type error
});

TypeScript映射类型推断无法按预期工作

1 个答案: