Question

我对ASP.NET和MVC还是很陌生，目前正在尝试以下操作：

模型：表单的属性
视图：向用户显示表单
控制器：
- 动作：做点什么
- 返回初始视图并向用户显示值

使用普通的html我可以使用它。到目前为止，我使用剃刀语法无法在表单提交后重新显示这些值。

我的模特：

namespace MyModels
{
  public class SubmitTicketFormModel
  {
     [DisplayName("First Name")]
     public string _firstName { get; set; }

     [DisplayName("Last Name")]
     public string _lastName { get; set; }
  }
}

我的观点：

@model MyModels.SubmitTicketFormModel

@{
    ViewData["Title"] = "SubmitTicketView";
    Layout = "~/Views/Shared/_Layout.cshtml";
}

<h1>Request</h1>

@using (Html.BeginForm("SubmitTicketAction", "SubmitTicketContoller", FormMethod.Post))
{
    <div class="form-group">
        @Html.LabelFor(model => model._firstName)
        @Html.TextBoxFor(model => model._firstName, new { @class = "form-control" })

        @Html.LabelFor(model => model._lastName)
        @Html.TextBoxFor(model => model._lastName, new { @class = "form-control" })
    </div>

    <input type="submit" value="Post comment" />
}


<table class="table table-bordered table-sm">
    <thead class="thead-light">
        <tr>
            <th>col1</th>
            <th>col2</th>
        </tr>
    </thead>
    <tbody>

        <tr>
            <td>
                @Model._firstName
            </td>
            <td>
                @Model._lastName
            </td>
        </tr>

    </tbody>
</table>

控制器：

    public class SubmitTicketController : Controller
    {
        public ActionResult SubmitTicketView()
        {
            var TicketInstance = new SubmitTicketFormModel();
            return View(TicketInstance);
        }

        [HttpPost]
        public ActionResult SubmitTicketAction(SubmitTicketFormModel model)  
        {
            var NewTicketInstance = new SubmitTicketFormModel()
            {
                _firstName = model._firstName,
                _lastName = model._lastName
            };

            return View(NewTicketInstance);

        }
     }

 }

你能指导我正确的方向吗？

Answer 1

如果您希望在用户单击“提交”按钮后呈现相同的视图，那么我想您不希望该@using（Html.BeginForm（“ SubmitTicketAction”，“ SubmitTicketContoller”，FormMethod.Post）在用户界面再次显示。在您的视图中，只有名字和姓氏的值已经在视图中写下了逻辑。在这种情况下，您只需通过控制器在视图中传递一个ViewBag，这将帮助您的View理解它是显示输入表单还是显示用户输入的数据。

[HttpPost]
        public ActionResult SubmitTicketAction(SubmitTicketFormModel model)  
        {
            var NewTicketInstance = new SubmitTicketFormModel()
            {
                _firstName = model._firstName,
                _lastName = model._lastName
            };
            ViewBag.Check = "true";
            return View(ViewName , modelname);

        }

然后在您看来

@model MyModels.SubmitTicketFormModel

@{
    ViewData["Title"] = "SubmitTicketView";
    Layout = "~/Views/Shared/_Layout.cshtml";
}
@if(ViewBag.Check != null)
{
<h1>Request</h1>

@using (Html.BeginForm("SubmitTicketAction", "SubmitTicketContoller", FormMethod.Post))
{
    <div class="form-group">
        @Html.LabelFor(model => model._firstName)
        @Html.TextBoxFor(model => model._firstName, new { @class = "form-control" })

        @Html.LabelFor(model => model._lastName)
        @Html.TextBoxFor(model => model._lastName, new { @class = "form-control" })
    </div>

    <input type="submit" value="Post comment" />
}
}
else
{

<table class="table table-bordered table-sm">
    <thead class="thead-light">
        <tr>
            <th>col1</th>
            <th>col2</th>
        </tr>
    </thead>
    <tbody>

        <tr>
            <td>
                @Model._firstName
            </td>
            <td>
                @Model._lastName
            </td>
        </tr>

    </tbody>
</table>
}

在ASP.NET MVC中提交表单后显示值的最佳实践

1 个答案: