Question

这是我的Apollo客户代码：

    mutation  {
  createUser(user_id: 3333, username: "third user", email: "third@email.com", password: "supersecret"){
    user_id
    username
    email
    password
  }
}

下面是我的typedef模式：

const typeDef = gql 
`
    type Query {
        "These are the queries we define in our query type"
        me(user_id: ID): User
    }
    "How to define the structure of user? Below is an object type that does this:"
    type User {
        user_id: ID,
        username: String,
        email: String,
        password: String
    }

    type Mutation {
        createUser(username: String!, email: String!, password: String, user_id: ID): User!
    }
`;

此外，我在postgres中使用sequalize ORM，而我的dbIndex是这样的：

const Sequelize = require('sequelize');

require('dotenv').config();

const sortDb = new Sequelize(
    `${process.env.DATABASE}`,
    process.env.DATABASE_USER,
    process.env.DATABASE_PASSWORD,
    {
      dialect: 'postgres',
    },
);

sortDb
    .authenticate()
    .then(() => {
        console.log('Connected to SORT MY MIND DB');
    })
    .catch((err) => {
        console.error('Unable to connect to DB', err);
    });

// create a DB model which will correspond to 
const account = sortDb.define('account', {
    user_id: {type: Sequelize.INTEGER},
    username: {type: Sequelize.STRING},
    passowrd: {type: Sequelize.STRING},
    email: {type: Sequelize.STRING}
});

module.exports.account = account;

我的查询运行完美，并从postgres表中获取数据。为什么不运行突变？我看到以下错误：“正在执行（默认）：INSERT INTO“ accounts”（“ id”，“ user_id”，“ username”，“ email”，“ createdAt”，“ updatedAt”）VALUES（DEFAULT，$ 1，$ 2， $ 3，$ 4，$ 5）返回*; 未处理的拒绝SequelizeDatabaseError：“密码”列中的空值违反了非空约束”。

这显然意味着Apollo客户端正在尝试将所有空值侮辱到我的表中。我该如何解决？

Answer 1

嗯，这是dbIndex中的错字！！！ “密码” Phew：D

为什么即使指定了值，Apollo客户端为什么仍将所有字段的空值插入表中？

1 个答案: