Question

我尝试通过Ansible将路径添加到文本文件中用逗号分隔的路径列表中。

我的文本文件具有（或没有）属性paths，该属性包含路径列表。即path = path1，path2，path3
我想确保列表中存在路径（pathX），无论其位置如何，如果没有，则将其添加到末尾（如果没有行，则创建新的行路径= pathX）

我尝试使用正则表达式负前瞻的lineinfile模块失败

    lineinfile:
      path: /myfile
      state: present
      regexp: '^(paths =([\s,]+(?!pathX)[\w=\/\-\."]+)*)([\s,]*[\w=\/\-\."]+)*$'
      line: '\1\3, pathX'
      backrefs: yes

不存在路径时，我要插入paths = pathX
当paths = path1时，我想拥有paths = path1, pathX
当paths = path1, pathX时，我想拥有paths = path1, pathX
当paths = pathX, path1时，我想拥有paths = pathX, path1（或path1, pathX之类的东西）

Answer 1

有点粗糙，但是可以用：

---
- name: Fix line
  hosts: localhost
  connection: local

  tasks:
  - name: get line from file
    command: grep '^paths = ' file
    register: grep
    failed_when: false

  - name: Add line if not present
    lineinfile:
      path: file
      state: present
      line: "paths = pathX"
    when: grep.rc != 0

  - name: Ensure pathX is in line
    lineinfile:
      path: file
      regexp: '^paths = path1'
      state: present
      line: "paths = path1, pathX"
    when: "'paths = path1' in grep.stdout"

  - name: Ensure path1 is in line
    lineinfile:
      path: file
      regexp: '^paths = pathX'
      state: present
      line: "paths = pathX, path1"
    when: "'paths = pathX' in grep.stdout"

您不必在单个任务中做任何事情。

如果列表中尚不存在该如何添加项目？

1 个答案: