我在Bigquery中有一个关系数据集,其中包含两个表。
第一个表保存客户数据
mixedsort(sub("W(\\d{1})_", "W0\\1_", names(df)))
#[1] "W01_2019" "W02_2019" "W03_2019" "W10_2018" "W50_2018" "W51_2018" "W52_2018"
第二个表在第一个表中包含与客户相关的各种名称/值对:
+-------------+--------+
| Customer ID | Name |
+-------------+--------+
| 1 | Bob |
+-------------+--------+
| 2 | Jenny |
+-------------+--------+
| 3 | Janice |
+-------------+--------+
我想生成一个枚举每个客户的报告,并在表2中找到的每个name:value下设置一个TRUE,例如:
+-------------+----------+-------+
| Customer ID | Category | Value |
+-------------+----------+-------+
| 1 | A | A |
+-------------+----------+-------+
| 1 | A | B |
+-------------+----------+-------+
| 1 | B | A |
+-------------+----------+-------+
| 2 | B | B |
+-------------+----------+-------+
我尝试将每个category:value组合指定为我的select语句中的列
+-------------+------+------+-----+------+------+
| Customer ID | A:A | A:B | A:C | B:A | B:B |
+-------------+------+------+-----+------+------+
| 1 | TRUE | TRUE | | TRUE | |
+-------------+------+------+-----+------+------+
| 2 | | | | | TRUE |
+-------------+------+------+-----+------+------+
| 3 | | | | | |
+-------------+------+------+-----+------+------+
但这并没有给我任何好处,因为一旦找到该值,我就不知道如何获取将单元格设置为TRUE的查询。
很抱歉,我很不熟悉SQL。
答案 0 :(得分:1)
您需要某种聚合,例如:
select t1.customer_id,
bool_or(t2.category = 'a' and t2.value = 'a') as a_a,
bool_or(t2.category = 'a' and t2.value = 'b') as a_b,
bool_or(t2.category = 'a' and t2.value = 'c') as a_c,
bool_or(t2.category = 'b' and t2.value = 'a') as b_a,
bool_or(t2.category = 'b' and t2.value = 'b') as b_b
from table_1 t1 join
table_2 t2
on t1.customer_id = t2.customer_id
group by t1.customer_id;
答案 1 :(得分:1)
以下是用于BigQuery标准SQL
#standardSQL
SELECT customer_id,
LOGICAL_OR((category, value) = ('A', 'A')) AS a_a,
LOGICAL_OR((category, value) = ('A', 'B')) AS a_b,
LOGICAL_OR((category, value) = ('A', 'C')) AS a_c,
LOGICAL_OR((category, value) = ('B', 'A')) AS b_a,
LOGICAL_OR((category, value) = ('B', 'B')) AS b_b
FROM `project.dataset.table1`
JOIN `project.dataset.table2`
USING (customer_id)
GROUP BY customer_id
您可以使用问题中的示例数据来测试,玩游戏,如下例所示
#standardSQL
WITH `project.dataset.table1` AS (
SELECT 1 Customer_ID, 'Bob' Name UNION ALL
SELECT 2, 'Jenny' UNION ALL
SELECT 3, 'Janice'
), `project.dataset.table2` AS (
SELECT 1 Customer_ID, 'A' Category, 'A' Value UNION ALL
SELECT 1, 'A', 'B' UNION ALL
SELECT 1, 'B', 'A' UNION ALL
SELECT 2, 'B', 'B'
)
SELECT customer_id,
LOGICAL_OR((category, value) = ('A', 'A')) AS a_a,
LOGICAL_OR((category, value) = ('A', 'B')) AS a_b,
LOGICAL_OR((category, value) = ('A', 'C')) AS a_c,
LOGICAL_OR((category, value) = ('B', 'A')) AS b_a,
LOGICAL_OR((category, value) = ('B', 'B')) AS b_b
FROM `project.dataset.table1`
JOIN `project.dataset.table2`
USING (customer_id)
GROUP BY customer_id
有结果
Row customer_id a_a a_b a_c b_a b_b
1 1 true true false true false
2 2 false false false false true
如果您需要/想要的输出与问题完全相同,可以使用以下调整后的版本
#standardSQL
SELECT customer_id,
IF(LOGICAL_OR((category, value) = ('A', 'A')), 'TRUE', '') AS a_a,
IF(LOGICAL_OR((category, value) = ('A', 'B')), 'TRUE', '') AS a_b,
IF(LOGICAL_OR((category, value) = ('A', 'C')), 'TRUE', '') AS a_c,
IF(LOGICAL_OR((category, value) = ('B', 'A')), 'TRUE', '') AS b_a,
IF(LOGICAL_OR((category, value) = ('B', 'B')), 'TRUE', '') AS b_b
FROM `project.dataset.table1`
JOIN `project.dataset.table2`
USING (customer_id)
GROUP BY customer_id
有结果
Row customer_id a_a a_b a_c b_a b_b
1 1 TRUE TRUE TRUE
2 2 TRUE
注意:在上面的示例中-您实际上不需要联接,因为您没有使用table1中的字段,而不是用作过滤器(仅显示table1中的用户)