Question

如何从函数内部传递值并将其添加到函数外部，以便创建得分计数器？

嗨，所以我是新手，并且在这部分上停留了一段时间。我正在尝试编写代码，将每次掷骰子的分数相加，然后重新掷骰子，并在每次用户告诉时添加新的分数和上一个分数。我尝试将其作为循环执行，但代码仅显示相同的数字。我在做什么错了，我该如何改善？

import random

die1 = (random.randint(1, 6))
score = 0
score = die1 + score

def onroll():
        print("Do you want to roll again?")
        if "y" in input():
            print(die1)
            print(score)
            onroll()


onroll()

Answer 1

由于您是编码的新手，因此如果您在跳入之前遵循快速的python教程，将会发现很多乐趣。

Python是一种有趣的编程语言，相当直观，但是只有在您学习了基础知识之后，它才是直观的：）。

在线上有一些不错的教程，例如tutorialspoint。

话虽如此，我将帮助您从基本的角度理解这一点。

import random

die1 = (random.randint(1, 6))
score = 0
score = die1 + score

# A function can take several inputs such as:
# def onroll(input1, input2):
# def onroll(myInput):

# In your case you want to pass a die and a score, so lets pass that
def onroll(score, die):
        print("Do you want to roll again?")
        if "y" in input():
            print(die)
            print(score)

            # This is recursion, which is an advanced topic.
            # That being said if you want to `return` values we need
            # to add a return here.
            # and we need to re-pass our arguments
            return onroll(score, die)
        # Now we can return our die and score
        return die, score


# Now call the method
result_die, result_score = onroll(score, die1)
# And we can print the results.
print(result_die, result_score)

Answer 2

这就是我要做的：

import random


def roll():
    return random.randint(1, 6)


score = 0
role_question = "Do you want to roll?"

print role_question
while "y" in raw_input():
    die1 = roll()
    score += die1
    print "Rolled: " + str(die1)
    print "Score: " + str(score)
    print role_question

如何创建一个计分计数器，使其从循环中添加一个值

2 个答案: