我正在使用以下SQL查询来获取记录集。
;WITH SFPIPELINE AS (
SELECT
PIPELINE_STRING,
PACKET_NUMBER,
PIPELINE_NUMBER
FROM
[RTMASTER].[DBO].[SF_PIPELINE]
WHERE
PIPELINE_STRING IN (
'SOLUTION_TEST',
'2018.01_SVC_SANDBOX',
'2018.01_SVC_ENG'
)
AND PACKET_NUMBER IN (98, 1090, 1092)
),
PROJ_INST_PIPELINE AS (
SELECT
DISTINCT PIP.PROJECT_INSTANCE_PIPELINE_ID,
PIP.PROJECT_INSTANCE_ID,
PIP.PACKET_NUMBER,
PIP.PROJECT_NUMBER,
PIP.SOURCE_SET_INSTANCE,
SFP.PIPELINE_STRING
FROM
PROJECT_INSTANCE_PIPELINE PIP
INNER JOIN SFPIPELINE SFP ON PIP.PACKET_NUMBER = SFP.PACKET_NUMBER
AND PIP.PIPELINE_NUMBER = SFP.PIPELINE_NUMBER
AND PIP.ACTIVE = 1
AND PIP.PROJECT_INSTANCE_PIPELINE_ID >= 20481038
),
PROJ_INST_BASE AS (
SELECT
PIP.PROJECT_INSTANCE_PIPELINE_ID,
PIP.PROJECT_NUMBER,
PIP.PACKET_NUMBER,
PIP.PIPELINE_STRING,
PIP.SOURCE_SET_INSTANCE,
PIP.PROJECT_INSTANCE_ID,
PIB.ORIGINAL_PROMOTER,
PIB.DEV_INSTANCE,
PROJECT_TYPE_NUMBER,
PIB.SUBVERSION_PROJECT_REVISION,
PIB.SUBVERSION _PROJECT_URL,
PIB.Front_End,
PIB.Back_End
FROM
PROJECT_INSTANCE_BASE PIB
INNER JOIN PROJ_INST_PIPELINE PIP ON PIB.PROJECT_INSTANCE_ID = PIP.PROJECT_INSTANCE_ID
AND PIP.PROJECT_NUMBER = PIB.PROJECT_NUMBER
AND PIB.PROJECT_TYPE_NUMBER IN (5, 105, 106)
),
SF_PROJ AS (
SELECT
PJTINST.PROJECT_INSTANCE_PIPELINE_ID,
PJTINST.PROJECT_INSTANCE_ID,
PJTINST.PROJECT_NUMBER,
PJTINST.PIPELINE_STRING,
PJTINST.ORIGINAL_PROMOTER,
PJTINST.SOURCE_SET_INSTANCE,
PJTINST.PROJECT_TYPE_NUMBER,
PJTINST.PACKET_NUMBER,
SFP.PROJECT_NAME,
PJTINST.SUBVERSION_PROJECT_REVISION,
PJTINST.SUBVERSION_PROJECT_URL,
PJTINST.Front_End,
PJTINST.Back_End
FROM
DBO.SF_PROJECT SFP
INNER JOIN PROJ_INST_BASE PJTINST ON SFP.PROJECT_NUMBER = PJTINST.PROJECT_NUMBER
),
USER_DETAIL AS (
SELECT
SFP.PROJECT_NAME,
SFP.PROJECT_NUMBER,
SFP.PROJECT_TYPE_NUMBER,
SFP.SOURCE_SET_INSTANCE,
SFP.PACKET_NUMBER,
SFP.PIPELINE_STRING,
SFP.SUBVERSION_PROJECT_REVISION,
SFP.SUBVERSION_PROJECT_URL,
SFP.PROJECT_INSTANCE_PIPELINE_ID,
SFP.PROJECT_INSTANCE_ID,
AIAA.EMAIL_ADDRESS,
SFP.Front_End,
SFP.Back_End
FROM
SF_ASSOCIATE_INFO_ALL_ASSOCIATES AIAA
INNER JOIN SF_PROJ SFP ON AIAA.OPER_ID = SFP.ORIGINAL_PROMOTER
),
FINAL AS (
SELECT
UD.PROJECT_NAME,
FP.Feature_Number,
UD.PROJECT_NUMBER,
UD.PROJECT_TYPE_NUMBER,
UD.SOURCE_SET_INSTANCE,
UD.PACKET_NUMBER,
UD.PIPELINE_STRING,
UD.SUBVERSION_PROJECT_REVISION,
UD.SUBVERSION_PROJECT_URL,
UD.PROJECT_INSTANCE_PIPELINE_ID,
UD.PROJECT_INSTANCE_ID,
UD.EMAIL_ADDRESS,
UD.Front_End,
UD.Back_End
FROM
[RTMaster].[dbo].[Feature_Projects_History] FP
INNER JOIN USER_DETAIL UD ON FP.Project_Instance_Pipeline_ID = UD.PROJECT_INSTANCE_PIPELINE_ID
)
SELECT
*
FROM
FINAL
查询工作正常，只有记录没有排序。
我想对PROJECT_INSTANCE_PIPELINE_ID使用order by，以便对所有行进行排序。当我使用ORDER BY子句时，看到以下错误。
错误： 除非还指定了TOP，OFFSET或FOR XML，否则ORDER BY子句在视图，内联函数，派生表，子查询和公用表表达式中无效。
不确定如何将Order By和With Clause一起使用。
任何想法！
答案 0 :(得分：0)
尝试如下，我只是在PROJECT_NAME中使用了order by
WITH SFPIPELINE AS
(SELECT PIPELINE_STRING, PACKET_NUMBER, PIPELINE_NUMBER FROM [RTMASTER].[DBO].[SF_PIPELINE]
WHERE PIPELINE_STRING IN ( 'SOLUTION_TEST', '2018.01_SVC_SANDBOX', '2018.01_SVC_ENG')
AND PACKET_NUMBER IN (98, 1090, 1092)),
PROJ_INST_PIPELINE AS
(SELECT DISTINCT PIP.PROJECT_INSTANCE_PIPELINE_ID, PIP.PROJECT_INSTANCE_ID, PIP.PACKET_NUMBER, PIP.PROJECT_NUMBER, PIP.SOURCE_SET_INSTANCE, SFP.PIPELINE_STRING FROM PROJECT_INSTANCE_PIPELINE PIP
INNER JOIN SFPIPELINE SFP ON PIP.PACKET_NUMBER = SFP.PACKET_NUMBER AND PIP.PIPELINE_NUMBER = SFP.PIPELINE_NUMBER AND PIP.ACTIVE = 1
AND PIP.PROJECT_INSTANCE_PIPELINE_ID >= 20481038),
PROJ_INST_BASE AS
(SELECT PIP.PROJECT_INSTANCE_PIPELINE_ID, PIP.PROJECT_NUMBER, PIP.PACKET_NUMBER, PIP.PIPELINE_STRING, PIP.SOURCE_SET_INSTANCE, PIP.PROJECT_INSTANCE_ID, PIB.ORIGINAL_PROMOTER, PIB.DEV_INSTANCE,PROJECT_TYPE_NUMBER, PIB.SUBVERSION_PROJECT_REVISION, PIB.SUBVERSION_PROJECT_URL,
PIB.Front_End, PIB.Back_End FROM PROJECT_INSTANCE_BASE PIB INNER JOIN PROJ_INST_PIPELINE PIP ON PIB.PROJECT_INSTANCE_ID = PIP.PROJECT_INSTANCE_ID AND PIP.PROJECT_NUMBER= PIB.PROJECT_NUMBER AND PIB.PROJECT_TYPE_NUMBER IN (5,105, 106)),
SF_PROJ AS
(SELECT PJTINST.PROJECT_INSTANCE_PIPELINE_ID, PJTINST.PROJECT_INSTANCE_ID, PJTINST.PROJECT_NUMBER, PJTINST.PIPELINE_STRING, PJTINST.ORIGINAL_PROMOTER, PJTINST.SOURCE_SET_INSTANCE, PJTINST.PROJECT_TYPE_NUMBER, PJTINST.PACKET_NUMBER, SFP.PROJECT_NAME,
PJTINST.SUBVERSION_PROJECT_REVISION, PJTINST.SUBVERSION_PROJECT_URL, PJTINST.Front_End, PJTINST.Back_End FROM DBO.SF_PROJECT SFP INNER JOIN PROJ_INST_BASE PJTINST ON SFP.PROJECT_NUMBER = PJTINST.PROJECT_NUMBER),
USER_DETAIL AS
(SELECT SFP.PROJECT_NAME, SFP.PROJECT_NUMBER, SFP.PROJECT_TYPE_NUMBER, SFP.SOURCE_SET_INSTANCE, SFP.PACKET_NUMBER, SFP.PIPELINE_STRING, SFP.SUBVERSION_PROJECT_REVISION, SFP.SUBVERSION_PROJECT_URL, SFP.PROJECT_INSTANCE_PIPELINE_ID, SFP.PROJECT_INSTANCE_ID, AIAA.EMAIL_ADDRESS, SFP.Front_End, SFP.Back_End
FROM SF_ASSOCIATE_INFO_ALL_ASSOCIATES AIAA INNER JOIN SF_PROJ SFP ON AIAA.OPER_ID = SFP.ORIGINAL_PROMOTER),
FINAL AS
(SELECT UD.PROJECT_NAME, FP.Feature_Number, UD.PROJECT_NUMBER, UD.PROJECT_TYPE_NUMBER, UD.SOURCE_SET_INSTANCE, UD.PACKET_NUMBER, UD.PIPELINE_STRING, UD.SUBVERSION_PROJECT_REVISION, UD.SUBVERSION_PROJECT_URL,
UD.PROJECT_INSTANCE_PIPELINE_ID, UD.PROJECT_INSTANCE_ID, UD.EMAIL_ADDRESS, UD.Front_End, UD.Back_End FROM [RTMaster].[dbo].[Feature_Projects_History] FP
INNER JOIN USER_DETAIL UD ON FP.Project_Instance_Pipeline_ID = UD.PROJECT_INSTANCE_PIPELINE_ID)
SELECT * FROM FINAL order by PROJECT_NAME -- use here others column name as you need