Question

我从API获取这种格式的 JOSN 。我在单独的键中获得列和行。可以将列和行连接到单个对象。

{
    "datasource": "xxxxxxxxxxxxxxxx",
    "columns": [
        "Last Activity Date-Time",
        "Name",
        "City",
        "Age",
        "Gender",
        "Initial Inquiry Date",
        "Status",
        "Anticipated_Move-in",
        "LastContacted",
        "NextStep",
        "Lead Score"
    ],
    "rows": [
        [
            "2019-03-07T12:56:00",
            "Harold Glucks",
            "",
            "",
            "",
            "03/05/2019",
            "LOST (No Potential for Move-In)",
            "",
            "03/07/2019",
            "Email                        ",
            "100"
        ],
        [
            "2018-05-14T10:23:00",
            "Lea Deitch",
            "",
            "",
            "Female",
            "05/17/2017",
            "LOST (No Potential for Move-In)",
            "",
            "05/14/2018",
            "Phone Call - Lead",
            "100"
        ],
        [
            "2019-02-08T13:19:00",
            "Donna Snoderly",
            "",
            "",
            "",
            "08/22/2018",
            "WARM (Move-In Likely in 30-60 Days)",
            "",
            "02/08/2019",
            "Email                        ",
            "100"
        ]
    ],
    "numRows": 3,
    "numColumns": 11,
    "fromcache": true
}

我尝试将列添加到数组，将行添加到另一个数组。合并此数组没有达到我的预期。我想将对象组织成这种格式，这可能吗？

[
    { 
        Last Activity Date-Time : "2019-03-07T12:56:00",
        Name: "Harold Glucks",
        City: "",
        Age: "",
        Gender: "",
        Initial Inquiry Date: "03/05/2019",
        Status: "LOST (No Potential for Move-In)",
        Anticipated_Move-in: "",
        LastContacted: "03/07/2019",
        NextStep: "Email",
        Lead Score: "100"
    },
    {
        Last Activity Date-Time : "2019-03-07T12:56:00",
        Name: "Harold Glucks",
        City: "",
        Age: "",
        Gender: "",
        Initial Inquiry Date: "03/05/2019",
        Status: "LOST (No Potential for Move-In)",
        Anticipated_Move-in: "",
        LastContacted: "03/07/2019",
        NextStep: "Email",
        Lead Score: "100"
    },
    {
        Last Activity Date-Time : "2019-03-07T12:56:00",
        Name: "Harold Glucks",
        City: "",
        Age: "",
        Gender: "",
        Initial Inquiry Date: "03/05/2019",
        Status: "LOST (No Potential for Move-In)",
        Anticipated_Move-in: "",
        LastContacted: "03/07/2019",
        NextStep: "Email",
        Lead Score: "100"
    }
]

Answer 1

您可以映射行并映射列作为键并获取对象。

var data = { datasource: "xxxxxxxxxxxxxxxx", columns: ["Last Activity Date-Time", "Name", "City", "Age", "Gender", "Initial Inquiry Date", "Status", "Anticipated_Move-in", "LastContacted", "NextStep", "Lead Score"], rows: [["2019-03-07T12:56:00", "Harold Glucks", "", "", "", "03/05/2019", "LOST (No Potential for Move-In)", "", "03/07/2019", "Email", "100"], ["2018-05-14T10:23:00", "Lea Deitch", "", "", "Female", "05/17/2017", "LOST (No Potential for Move-In)", "", "05/14/2018", "Phone Call - Lead", "100"], ["2019-02-08T13:19:00", "Donna Snoderly", "", "", "", "08/22/2018", "WARM (Move-In Likely in 30-60 Days)", "", "02/08/2019", "Email", "100"]], numRows: 3, numColumns: 11, fromcache: true }
    result = data.rows.map(a => Object.assign(...data.columns.map((k, i) => ({ [k]: a[i] }))));

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

使用lodash：

const obj = JSON.parse(json);

const merged = _.map(obj.rows, (r, i) => {
  return _.zipObject(obj.columns, r);
});

如何将JSON对象组织成键和值

2 个答案: