Question

我正在尝试创建一个新列表，对两个python列表执行逐元素构造，如下所示：

from operator import add

number_villains_players = 0
villain_strength = []
player_strength = []
resulten_strength = []

def get_villain_strength(size):
    villain_strength = [int(x) for x in input("Enter {} numbers of space separated strength of Villains:".format(size)).split()]
    print(villain_strength)

def get_player_strength(size):

    player_strength = [int(x) for x in input("Enter {} numbers of space separated energy of Players:".format(size)).split()]
    print(player_strength)

def compare_strength():
    #resulten_strength = [m-n for (m,n) in zip(player_strength,villain_strength)]     #doesn't work
    #resulten_strength = [sum(x) for x in zip(player_strength, villain_strength)]     #doesn't work
    #resulten_strength = [list( map(add, player_strength, villain_strength) )]     #doesn't work
    resulten_strength = [a*b for a,b in zip(player_strength,villain_strength)]     #doesn't work
    print(resulten_strength)

def main():
    number_villains_players = input("How many Players/Villains?:")
    get_villain_strength(number_villains_players)
    get_player_strength(number_villains_players)
    compare_strength()
    if (i > 0 for i in resulten_strength):
        print("WIN")
    else:
        print("LOSE")

main()

但是print(resulten_strength)始终为[]或[[]]

为空

我遵循了以下所有可能的解决方案：

有人可以指出我要去哪里吗？

Answer 1

您正在方法中分配本地列表，它们不是全局的。因此，定义的顶行始终为空。这应该可以解决您的问题：

#!/usr/bin/env python3
import cgi,cgitb
import urllib.request

from bs4 import BeautifulSoup
from bs4.element import Comment
from datetime import datetime
import re
import json

print ("Content-Type: text/plain;charset=utf-8\n")

print("hello")

但是在任何地方使用全局变量都是不好的。您可能想要一个带有返回值的函数。

在函数内分配相同的名称变量时，它将覆盖全局变量的名称，直到从函数返回为止。或者说，如果您查找变量，它将首先在def get_villain_strength(size): global villain_strength villain_strength = [int(x) for x in input("Enter {} numbers of space separated strength of Villains:".format(size)).split()] print(villain_strength)中查找名称，如果找不到任何内容，它将转到locals()。如果仍然找不到任何内容，则会引发异常。

Answer 2

我不确定这是您要找的东西。我对您的代码做了一些小的修改。我删除了变量声明并修改了函数。

def get_villain_strength(size):
    villain_strength = [int(x) for x in input("Enter {} numbers of space separated strength of Villains:".format(size)).split()]
    print (villain_strength)
    return(villain_strength)

def get_player_strength(size):

    player_strength = [int(x) for x in input("Enter {} numbers of space separated energy of Players:".format(size)).split()]
    print (player_strength)
    return(player_strength)

def compare_strength(x,y):        
    resulten_strength = [a*b for a,b in zip(x,y)]     
    return(resulten_strength)

def main():
    number_villains_players = input("How many Players/Villains?:")
    x = get_villain_strength(number_villains_players)
    y = get_player_strength(number_villains_players)
    print (compare_strength(x,y))

如何执行两个python列表的按元素构造？

2 个答案: