以图形方式格式化工具提示以获取长文本标签

Question

请考虑以下简单示例。有没有一种方法可以格式化绘图工具提示，使长文本标签在框中可见，而不是这个荒谬的矩形会截断值？

library(ggplot2); library(plotly)

df <- data.frame(x = 1:10, y = 1:10, z = rep("the longggggggggggggggggggggggggggggestttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttt labelllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllll you can imagineeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee", 10))

p <- ggplot(df, aes(x,y,label=z)) + geom_point()
ggplotly(p, tooltip = "label")

Answer 1

我很确定，某个地方存在更优雅的解决方案。我可以建议您像每个n字符一样休息一下。 https://stackoverflow.com/a/2352006/9300556有一个不错的解决方法：

gsub('(.{1,90})(\\s|$)', '\\1\n', s)

  

它将字符串“ s”分成最多90个字符的行（不包括   换行符“ \ n”，但包括单词间空格），   除非单词本身超过90个字符，否则该单词   本身将占据整条线。

所以我们只需要在gsub()美学中添加ggplot：

p <- ggplot(df, aes(x,y,
            text = gsub('(.{1,20})(\\s|$)', '\\1\n', z))) +
  geom_point()

ggplotly(p, tooltip = "text")

更新

这是@Rich Pauloo的评论中更为优雅的解决方案。在这种情况下，您的琴弦也大部分会被填充（但实际上会自动对齐）。但是，填充取决于绘图分辨率和标签位置。

library(stringr)

p <- ggplot(df,
            aes(x, y,
                text = stringr::str_wrap(
                  string = z,
                  width = 20,
                  indent = 1, # let's add extra space from the margins
                  exdent = 1  # let's add extra space from the margins
                ))) +
  geom_point()

ggplotly(p, tooltip = "text")