如果响应与Guzzle 6匹配某个值，如何实现重试处理程序

Question

我正在重写与API端点通信并在最终确定后收到最终响应的旧服务，他们称之为异步。

所以我的原始脚本使用了以下简化逻辑：

$response = $this->myCustomCurlResponseProcessor();
if ($response['state'] === 'started') {
    sleep(3);
}
$repeats = 0;
do {
    $response = $this->myCustomCurlResponseProcessor();
    if ($response['state'] === 'in_progress') {
        sleep(3);
    }
    $repeats++;
} while ($response['state'] === 'in_progress' && $repeats < 30);

if ($response['state'] !== 'finished') {
    throw new \RuntimeException('Failed to process request');
}
// process response

我很好奇是否可以通过异步请求处理此逻辑并重试中间件，例如：

$promise = $client->requestAsync('GET', 'data', [
    'query' => [
        //my params
    ]
]);
$promise->then(
    static function (ResponseInterface $res) {
        // handle only responses with state "finished"
        // other states like started, in_progress, failed should be handled elsewhere
    },
    static function (RequestException $e) {
        //handle error response
    }
);
$promise->wait();