Question

基本上我想得到两个计数。第一个计数是记录数。第二个计数是带有数据的记录数。这两个计数来自名为调查的表，该表并不具有所有的州名称。因此，我将其与另一个表UsState结合在一起以获取所有状态名称。我整理了语法，但出现错误。

SELECT
Name as State,
count (*)from NamrsFrozen2017.Investigation2017 where FiscalYear = 2017 AND StateName in (SELECT distinct StateName FROM [NamrsFrozen2017].[Investigation2017] WHERE (not ReportDate = '' ))[Report Date Records],
count (*) from NamrsFrozen2017.Investigation2017 WHERE FiscalYear = 2017 AND ReportDate != '' AND StateName in (SELECT distinct StateName FROM [NamrsFrozen2017].[Investigation2017] WHERE (not ReportDate = '' ))[Report Date Records with Data]
From
(SELECT DISTINCT Name FROM NamrsFullDw.UsState) s
LEFT JOIN NamrsFrozen2017.Investigation2017 c ON s.Name = c.StateName AND  c.FiscalYear = 2017
  GROUP BY Name
  Order by Name

Answer 1

一些相关的子查询将为您提供帮助。它们看起来像内联选择，但使用对内联查询之外的表的引用。像这样：

SELECT 
   Name as State,
   (SELECT COUNT(*) 
    FROM NamrsFrozen2017.Investigation2017 
    --I would think you want to view count of records for the current state, and not ALL states
    -- and not ALL states. So filter like this:
    WHERE FiscalYear = 2017 AND StateName = s.Name -- <-Correlated
    --Don't need a full list, like you had before
    -- (SELECT distinct StateName FROM [NamrsFrozen2017].[Investigation2017] WHERE (not ReportDate = '' ))
   ) AS [Report Date Records],
   (SELECT COUNT(*) 
    FROM NamrsFrozen2017.Investigation2017 
    WHERE FiscalYear = 2017 AND StateName = s.Name -- <- correlated
        AND ReportDate != '' --or maybe ReportDate IS NOT NULL            
    --Don't need to query the full table after correlating this to your FROM clause
    --  in (SELECT distinct StateName FROM [NamrsFrozen2017].[Investigation2017] WHERE (not ReportDate = '' ))
   ) AS [Report Date Records with Data]
FROM
   (SELECT DISTINCT Name FROM NamrsFullDw.UsState) s
   LEFT JOIN NamrsFrozen2017.Investigation2017 c 
        ON s.Name = c.StateName AND c.FiscalYear = 2017
GROUP BY s.Name
ORDER BY s.Name

这可能会进行更多优化，但是我对您的数据不熟悉，或者不清楚您到底要用原始查询来完成什么。

Answer 2

评论太久了。

您收到的语法错误是因为内联子查询的格式不正确。您不能以COUNT(*)函数开头；它们每个都需要完整的SELECT语句。然后，需要将每一个都用括号括起来。

这就是您的查询的样子。

SELECT
  Name AS State
 ,(
    SELECT
      COUNT(*)
    FROM
      NamrsFrozen2017.Investigation2017
    WHERE
      FiscalYear = 2017
      AND StateName IN
          (
            SELECT DISTINCT StateName
            FROM NamrsFrozen2017.Investigation2017
            WHERE ReportDate <> ''
          )
  ) AS [Report Date Records]
 ,(
    SELECT
      COUNT(*)
    FROM
      NamrsFrozen2017.Investigation2017
    WHERE
      FiscalYear = 2017
      AND ReportDate != ''
      AND StateName IN
          (
            SELECT DISTINCT StateName
            FROM NamrsFrozen2017.Investigation2017
            WHERE (NOT ReportDate = '')
          )
  ) AS [Report Date Records with Data]
FROM
  (SELECT DISTINCT Name FROM NamrsFullDw.UsState) AS s
LEFT JOIN
  NamrsFrozen2017.Investigation2017 AS c
    ON
    s.Name = c.StateName
      AND c.FiscalYear = 2017
GROUP BY
  Name
ORDER BY
  Name;

这里还有一个第二个问题，那就是该查询是否会执行您期望的操作。就Larnu的评论而言，聚合函数在不同情况下对NULL的处理方式不同。但是，如果没有可供测试的样本数据，我无法确定此功能版本的查询是否会返回您想要的结果。

有没有一种方法可以用一种语法选择带有不同子查询的两个计数？

2 个答案: