Question

我需要用多列数字替换字符串。下面是一个示例数据集：

x <- c("Low Outlier", "High Outlier", "Novice", "Novice", "Emerging", NA, "Proficient", "Approaching")
y <- c("Novice", "Approaching", "Proficient", "Approaching", "High Outlier", "Proficient",NA, "Emerging")
z <- c("High Outlier", "Proficient", "Approaching", "Emerging", "Low Outlier", "Approaching", "Approaching", "Emerging")

sam <- cbind(x,y,z)

我需要将“高/低异常值”转换为0，将NA保留为NA，将“新手”转换为1，将“新兴”转换为2，将“接近”转换为3，将“熟练”转换为4。 / p>

我尝试用转换单个变量

sam$x.r <- recode(sam$x.r,'Low Outlier'=0,'High Outlier'=0,'Novice'=1,'Emerging'=2,'Approaching'=3, 'Proficient'=4)

我收到一条错误消息“警告消息：在recode.numeric（Dat17_18.1 $ I.E.ScoreStat中，Low Outlier = 0，High Outlier = 0 ，：强制引入的NAs”

我不确定如何一次重新编码所有变量。

Answer 1

只需这样做-

=IF(A2="First Line",C3,IF(A1="",C1,Match("First Line",A2:A500,0)))

Answer 2

在这种情况下，我们可以使用case_when中的dplyr

library(dplyr)

sam %>%
   mutate_all(~case_when(. %in% c("Low Outlier", "High Outlier") ~ '0', 
                   . == "Novice" ~ '1', 
                   . == "Emerging" ~ '2', 
                   . == "Approaching" ~ '3', 
                   . == "Proficient" ~ '4', 
                   TRUE ~ NA_character_))


#     x    y z
#1    0    1 0
#2    0    3 4
#3    1    4 3
#4    1    3 2
#5    2    0 0
#6 <NA>    4 3
#7    4 <NA> 3
#8    3    2 2

但是，由于原始列也是字符，因此最终输出中包含字符列。如果需要，我们可以添加mutate_all(as.numeric)将其转换为数字。

数据

x <- c("Low Outlier", "High Outlier", "Novice", "Novice", "Emerging", NA, 
      "Proficient", "Approaching")
y <- c("Novice", "Approaching", "Proficient", "Approaching", "High Outlier", 
      "Proficient",NA, "Emerging")
z <- c("High Outlier", "Proficient", "Approaching", "Emerging", "Low Outlier", 
      "Approaching", "Approaching", "Emerging")
sam <- data.frame(x,y,z, stringsAsFactors = FALSE)

Answer 3

真的很重复又很快。这是一个简单的函数：

my_replacer<-function(df,y,z){    
df<-as.data.frame(apply(df,2,function(x) gsub(y,z,x)))
    #y is what you want to replace
    #z is the replacement
    #This uses regex
      df
    }
    my_replacer(sam,"Emerging.*","2")

这是我的用法：

library(dplyr)#can use ifelse. Still repetitive

    sam<-as.data.frame(sam)

    sam %>% 
      mutate_if(is.factor,as.character)->sam
    my_replacer(sam,"Emerging.*","2")

结果：

               x            y            z
    1  Low Outlier       Novice High Outlier
    2 High Outlier  Approaching   Proficient
    3       Novice   Proficient  Approaching
    4       Novice  Approaching            2
    5            2 High Outlier  Low Outlier
    6         <NA>   Proficient  Approaching
    7   Proficient         <NA>  Approaching
    8  Approaching            2            2

替换其他人

my_replacer(sam,"Novi.*","1")
             x            y            z
1  Low Outlier            1 High Outlier
2 High Outlier  Approaching   Proficient
3            1   Proficient  Approaching
4            1  Approaching     Emerging
5     Emerging High Outlier  Low Outlier
6         <NA>   Proficient  Approaching
7   Proficient         <NA>  Approaching
8  Approaching     Emerging     Emerging

Answer 4

我将使用命名向量作为映射

library(dplyr)
mapping = c("High Outlier" = 0, "Low Outlier" = 0, "Novice" = 1, "Emerging" = 2, "Approaching" = 3, "Proficient" = 4)

sam %>% 
  as.data.frame() %>% 
  mutate_all(function(i) mapping[i])

Answer 5

另一种使用factors进行重新编码并使用approxfun进行赋值的解决方案：

sam[] <- approxfun(1:5, c(0:3, 0))(
      as.numeric(factor(sam, 
                        c("Low Outlier", "Novice",  
                          "Emerging", "Approaching", 
                          "Proficient", "High Outlier"))))

#      x   y   z  
# [1,] "0" "1" NA 
# [2,] NA  "3" "0"
# [3,] "1" "0" "3"
# [4,] "1" "3" "2"
# [5,] "2" NA  "0"
# [6,] NA  "0" "3"
# [7,] "0" NA  "3"
# [8,] "3" "2" "2"

一次用多个列中的值替换字符串

5 个答案: