Question

我正在尝试获取Google搜索中的第一个URL。就像我在Google上搜索“ tcs”一样，它给出了http://www.tcs.com/。大多数情况下结果是正确的，但有时我没有获得正确的URL。我想要一个解决方案。在Google搜索上尝试以下操作：-“ Euler Baubetr。u。Bauleitungsges。mbH” 结果即将到来：-https://www.firmenwissen.com/.../EULER_BAUBETREUUNG_UND_ BAULEITUNGSGESELLSCHAFT_MBH.html

中间的输出URL中的

即将到来

，所需的输出是：-https://www.firmenwissen.com/en/az/firmeneintrag/63654/6110225969/EULER_BAUBETREUUNG_UND_BAULEITUNGSGESELLSCHAFT_MBH.html

代码：-

   import requests

   from bs4 import BeautifulSoup as bs

   var="Euler Baubetr. u. Bauleitungsges. mbH"

   goog_search = "https://www.google.co.uk/search?sclient=psyab&client=ubuntu&hs=k5b&channel=fs&biw=1366&bih=648&noj=1&q=" + var


   r = requests.get(goog_search)

   soup = bs(r.text, "html.parser")

   url=soup.find('cite').text

   print(url)

Answer 1

您应该浏览正确的href以获取网址，请参见下面的代码...

func createCloud () {
    for i in 0...3 {
        let background = SKSpriteNode(imageNamed: "test")
        background.name = "Test"
        background.size = CGSize(width: frame.size.width, height: 
        frame.size.height * 2)
        background.zPosition = 0
    //  background.position = CGPoint(x:  -(self.frame.size.width), y: CGFloat(i) * background.size.height)
        self.addChild(background)
    }
}


func moveCloud () {
    self.enumerateChildNodes(withName: "Test", using: ({ (node, error) in
        node.position.y -= 2

        if node.position.y < -((self.scene?.size.width)!) {
            node.position.y += ( self.scene?.size.width)! * 3
        }

    }))
}

如何使用python在Google搜索中获取正确的网址

代码：-

1 个答案: