Question

如何编写方法，该方法在输出时会将具有字符“ _”的键转换为空格。同时，我们不能绑定快捷键，而要使该方法具有通用性，它将自身进行查找和转换。

const arr = [{
        "name": "BMW",
        "price": "55 000",
        "color": "red",
        "constructor_man": "Billy%Zekun" //should become "constructor man"
    }, {
        "name": "MERSEDEC",
        "price": "63 000",
        "color": "blue",
        "constructor_man": "Jon%Adams" //should become "constructor man"
    }, {
        "name_car": "Lada", //should become "name car"
        "price": "93 000",
        "color": "blue",
        "constructor_man": "Bar John", //should become "constructor man"
        "door": "3"
    }, {
        "name": "TOYOTA",
        "price": "48 000",
        "color": "blue",
        "constructor_man": "Jon Hubert", //should become "constructor man"
        "door": "3",
        "max_people": "7" //should become "max people"
    }
];

Answer 1

您使用for...of在数组中循环。然后使用for...in遍历每个对象。如果键为includes _，请替换为' '。用_ delete键：

const arr = [{"name":"BMW","price":"55 000","color":"red","constructor_man":"Billy%Zekun"},{"name":"MERSEDEC","price":"63 000","color":"blue","constructor_man":"Jon%Adams"},{"name_car":"Lada","price":"93 000","color":"blue","constructor_man":"Bar John","door":"3"},{"name":"TOYOTA","price":"48 000","color":"blue","constructor_man":"Jon Hubert","door":"3","max_people":"7"}];

for (let item of arr) {
  for (let key in item) {
    if (key.includes('_')) {
      item[key.replace(/_/g, ' ')] = item[key];
      delete item[key]
    }
  }
}

console.log(arr)

Answer 2

您可以使用以下方法：

const arr = [{
		"name": "BMW",
		"price": "55 000",
		"color": "red",
		"constructor_man": "Billy%Zekun" //should become "constructor man"
	}, {
		"name": "MERSEDEC",
		"price": "63 000",
		"color": "blue",
		"constructor_man": "Jon%Adams" //should become "constructor man"
	}, {
		"name_car": "Lada", //should become "name car"
		"price": "93 000",
		"color": "blue",
		"constructor_man": "Bar John", //should become "constructor man"
		"door": "3"
	}, {
		"name": "TOYOTA",
		"price": "48 000",
		"color": "blue",
		"constructor_man": "Jon Hubert", //should become "constructor man"
		"door": "3",
		"max_people": "7" //should become "max people"
	}
];
const underscoreReplacer = src => src.map(item => Object.entries(item).reduce((obj,keyValue) => {obj[keyValue[0].replace('_',' ')]=keyValue[1];return obj},{}));
console.log(underscoreReplacer(arr));

.as-console-wrapper {
  max-height:100% !important;
  top: 0;
}

Answer 3

var underScoreReplacer = function(myArray){
    var temp = [];
    myArray.forEach(object => {
       var tempObj = {};
       Object.keys(object).forEach(key => {
            tempObj[key.replace("_", "#")] = object[key];
       });
       temp.push(tempObj);
    });
    return temp;
}

var myArray = [
   {
    name:"BMW",
    price:"55 000", 
    color:"red",
    constructor_man:"Billy%Zekun" //should become "constructor man"
    }
];

myArray = underScoreReplacer(myArray);
console.log(myArray);

从数组中删除/替换JS字符的方法

3 个答案: